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2 years ago

I NEED HELLP PLZZZZZZZZZZZ

Mathematics

2 answers:

SVEN [57.7K]2 years ago

6 0

20.41
(one pound is .454 kilograms)

marysya [2.9K]2 years ago

4 0

Answer:

45 lb is about 20.412; rounding it would be 20.4

Step-by-step explanation:

1 kg is about 2 pounds. (Used a conversion thing).

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A snowstorm began at noon, and snow had fallen at a constant rate per hour. If the depth of the snow was 21 inches at 5 o’clock

Anna007 [38]

Answer:

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Step-by-step explanation:

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3 years ago

Rewrite the function f(x) = -2(x+3)^2 – 8 in the form f (x) = ax²+bx+c.

OverLord2011 [107]

Answer:

-2x^{2}-12x-26

Step-by-step explanation:

(x+3)^2 = x^2+6x+9

-2(x^2+6x+9)-8

-2x^2-12x-18-8

-2x^2-12x-26

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3 years ago

PLZ HELP vgffdhstudfhgxd

olga55 [171]

Answer:

1/5

Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

Translate the following phrase into an algebraic expression. Do not simplify. Use the variable name x or y to describe the unkno

sweet [91]

Answer:

the algebraic expression for the phrase 4 divided by the sum of 4 and a number is $\mathbf{\frac{4}{4+x}}$

Step-by-step explanation:

Translate the following phrase into an algebraic expression.

We will use x to describe the unknown.

The phrase is: 4 divided by the sum of 4 and a number

The sum of 4 and a number can be written as: 4+x

4 divided by the sum of 4 and a number can be written into algebraic expression as: $\frac{4}{4+x}$

So, the algebraic expression for the phrase 4 divided by the sum of 4 and a number is $\mathbf{\frac{4}{4+x}}$

8 0

3 years ago

A company services home air conditioners. It is known that times for service calls follow a normal distribution with a mean of 7

SCORPION-xisa [38]

Answer:

The probability that exactly eight of them take more than 93.6 minutes is 5.6015 $\times 10^{-6}$ .

Step-by-step explanation:

We are given that it is known that times for service calls follow a normal distribution with a mean of 75 minutes and a standard deviation of 15 minutes.

A random sample of twelve service calls is taken.

So, firstly we will find the probability that service calls take more than 93.6 minutes.

Let X = times for service calls.

So, X ~ Normal( $\mu=75,\sigma^{2} =15^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean time = 75 minutes

$\sigma$ = standard deviation = 15 minutes

Now, the probability that service calls take more than 93.6 minutes is given by = P(X > 93.6 minutes)

P(X > 93.6 min) = P( $\frac{X-\mu}{\sigma}$ > $\frac{93.6-75}{15}$ ) = P(Z > 1.24) = 1 - P(Z $\leq$ 1.24)

= 1 - 0.8925 = 0.1075

The above probability is calculated by looking at the value of x = 1.24 in the z table which has an area of 0.8925.

Now, we will use the binomial distribution to find the probability that exactly eight of them take more than 93.6 minutes, that is;

$P(Y = y) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; y = 0,1,2,3,.........$

where, n = number of trials (samples) taken = 12 service calls

r = number of success = exactly 8

p = probability of success which in our question is probability that

it takes more than 93.6 minutes, i.e. p = 0.1075.

Let Y = Number of service calls which takes more than 93.6 minutes

So, Y ~ Binom(n = 12, p = 0.1075)

Now, the probability that exactly eight of them take more than 93.6 minutes is given by = P(Y = 8)

P(Y = 8) = $\binom{12}{8}\times 0.1075^{8} \times (1-0.1075)^{12-8}$

= $495 \times 0.1075^{8} \times 0.8925^{4}$

= 5.6015 $\times 10^{-6}$ .

6 0

3 years ago