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3 years ago

Write an equation in the form y= mx+ b

Mathematics

1 answer:

balu736 [363]3 years ago

6 0

Answer:

y = -6x + 360

Step-by-step explanation:

y = mx + b

b = 360

240 - 300 / 20 - 10

-60 / 10

-6

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Perform the indicated operation g(x)=-x-3 h(x) = x 2+X Find (goh) (x)

Klio2033 [76]

Answer:

$(g\circ h)(x)=-x^2-x-3$

Step-by-step explanation:

So we have the two functions:

$g(x)=-x-3\text{ and } h(x)=x^2+x$

And we want to find:

$(g\circ h)(x)$

This is the same thing as:

$=g(h(x))$

So, substitute h(x) into g(x):

$g(x)=-x-3\\g(h(x))=-(x^2+x)-3$

Distribute the negative:

$g(h(x))=-x^2-x-3$

And we're done!

So:

$(g\circ h)(x)=-x^2-x-3$

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Write an equation in the form y= mx+ b ​

Write an equation in the form y= mx+ b