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Which of the following is the same as 58%?

Alecsey [184]

Answer:

58%=0.58

Step-by-step explanation:

6 0

3 years ago

Part A: what is the area of the parallelogram? Show your work

Naily [24]

Answer:

2 foot

Step-by-step explanation:

A= L x W

A= 2/3 x 3

2= 2/3 x 3

split the parallelogram from A to C and divide the area by 2 to get 1 for each triangle.

4 0

3 years ago

Can you explain with steps

bonufazy [111]

Answer:

Yep

1. Click ask question at the top

2. type your question or add a picture

3. then click Ask

but you messed up in step 2 because you didn’t add a picture! Your Welcome

Step-by-step explanation:

5 0

3 years ago

4.) A bag contains 10 red marbles and 5 blue marbles. You randomly select 3 marbles from the bag. What is

sesenic [268]

Answer:

a) 1/27

b) 2/91

Step-by-step explanation:

A bag contains 10 red marbles and 5 blue marbles (15 marbles in total). You randomly select 3 marbles from the bag.

a) You replace each marble before selecting the next one.

The probability of selecting one blue marble is

$\dfrac{5}{15}=\dfrac{1}{3},$

then the probability that all 3 marbles are blue is

$\dfrac{1}{3}\times \dfrac{1}{3}\times \dfrac{1}{3}=\dfrac{1}{27}$

b) You do not replace each marble before selecting the next one. Each time the number of blue marbles decreases by 1 and the total number of marbles decreases by 1 too. So the probability that all 3 marbles are blue is

$\dfrac{5}{15}\times \dfrac{4}{14}\times \dfrac{3}{13}=\dfrac{2}{91}$

7 0

3 years ago

Of all sixth graders, 70% sent a text message yesterday. Ten trials of a simulation are conducted and the data are recorded belo

Effectus [21]

Answer:

80%

Step-by-step explanation:

According to the given data, the numbers 0 through 6 represent students who sent a text yesterday while the numbers 7 through 9 represent students who did not send a text yesterday.

Based on this key, we will calculate the number of students who sent the text yesterday and the number of students who did not sent the text yesterday.

The given data is: 62072, 34570, 80983, 04292, 83150, 36330, 96268, 14077, 77985, 13511

For each group we will identify how many students sent the text and how many students did not. According to the key, a number from 0 to 6 will be counted as a student who sent the text and a number from 7 to 9 will be counted as a student who did not send the text. Students who did not sent the text are made bold in the groups below.

62072: 4 students sent the text, 1 did not

34570: 4 students sent the text, 1 did not

80983: 2 students sent the text, 3 did not

04292: 4 students sent the text, 1 did not

83150: 4 students sent the text, 1 did not

36330: All 5 students sent the text

96268: 3 students sent the text, 2 did not

14077: 3 students sent the text, 2 did not

77985: 1 student sent the text, 4 did not

13511: All 5 students sent the text

We need to find the probability that 3 or more of a group of 5 students randomly selected will send a text today.

From the given groups, the number of groups where 3 or more students sent a text = 8

This represents our number of favorable or desired outcomes.

Total number of possible outcomes is the total number of groups = 10

Since, probability is defined as the ratio of number of favorable outcomes to total number of outcomes, based on the simulated data the probability that 3 or more of a group of 5 students randomly selected will send a text today will be = $\frac{8}{10}=0.80=80\%$

Thus, based on the simulated data there is 80% probability that 3 or more of a group of 5 students randomly selected will send a text today

5 0

3 years ago

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