Let, the first (smaller) number = x
Larger number = 8x
Then, 8x - x = 70
7x = 70
x = 70/7
x = 10
& 8(10) = 80
In short, Your Numbers would be, 10 & 80
Hope this helps!
7 unit to the left, means it is 7 less than -1.
-1-7 = -8
Ans: -8
Answer:
Here we have the function:
S(t) = 500 - 400*t^(-1)
Then the rate of change at the value t, will be:
S'(t) = dS(t)/dt
This differentiation will be:
S'(t) = -400/t^2
Then:
a) the rate of change at t = 1 is:
S'(1) = -400/1^2 = -400
The rate of change after one year is -400
b) t = 10
S'(10) = -400/10^2 = -400/100 = -4
The rate of change after 10 years is -4, it reduced as the years passed, as expected.
Step-by-step explanation:
what is the problem ? just take a deep breath, don't panic and think straight :
1) 12×k, which is usual written as 12k
2) u + 3
3) 1/5 × b = b/5
4) 10 - y
5) (a + 4) / 2
6) you did not say what is n summed with. so, I just designate this by "?".
(? + n) × 4
7) did you mean "take away one sixth from 4" ?
4 - 1/6
this can be simplified, as a whole number can be expressed by x/x (incl. 6/6). so, 4 = 4×6/6 = 24/6.
and so we have
24/6 - 1/6 = 23/6 = 3 5/6
8) d/2, often also written as d:2
9) 7 + v + w
10) the product of what with x ?
I designate this again by "?".
9 + ?x or
9 + ?×x or
9 + ?*x
