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sashaice [31]
3 years ago
5

Phone calls arrive at the rate of 48 per hour at the reservation desk for regional airways.

Mathematics
1 answer:
rosijanka [135]3 years ago
4 0

The different probabilities and number of callers expected to be waiting are;

A) P(x = 3) = 0.0286

B) P(x = 13) = 0.1056

C) 8 will be waiting

D) P(x = 0) = 0.0003

E) P(x = 0) = 0.0067

<h3>How to find probability using Poisson distribution?</h3>

We are given the rate of 48 phone calls per hour.

Thus, we will use poisson's distribution formula;

P(x) = (λˣ × e^(-λ))/x!

A) Probability of receiving three calls in a 10-minute interval of time which is P(x = 3). Thus;

λ = 48 * (10/60)

λ = 8

P(x = 3) = (8³ × e⁻⁸)/3!

P(x = 3) = 0.0286

B) Probability of receiving exactly 13 calls in 15 minutes is P(x = 13). Thus;

λ = 48 * (15/60)

λ = 12

P(x = 13) = (12¹³ × e⁻¹²)/13!

P(x = 13) = 0.1056

C) No calls are currently on hold and it takes 10 minutes to complete one call. Thus;

λ = 48 * (10/60)

λ = 8

Thus, 8 will be waiting after 10 minutes.

D) Probability that no one will be waiting is;

P(x = 0) = (8⁰ × e⁻⁸)/0!

P(x = 0) = 0.0003

E) No calls being processed and it takes 5 minutes for a personal time without being interrupted by a call. Thus;

λ = 48 * (5/60)

λ = 4

P(x = 0) = (4⁰ × e⁻⁵)/0!

P(x = 0) = 0.0067

Read more about probability with poisson's distribution at; brainly.com/question/7879375

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Harman [31]

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C = ((3.14 x 18) / 4) + 18

C = (56.52 / 4) + 18

C = 14.13 + 18

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Hope this helps! :)

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4 years ago
What is the value of the third quartile of the data set represented by this box plot?
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3 years ago
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A CBS News/New York Times opinion poll asked 1,190 adults whether they would prefer balancing the federal budget over cutting ta
nikklg [1K]

Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.0166 = 1.66% probability of a sample proportion of 0.59 or less.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sampling proportions of a proportion p in a sample of size n has mean \mu = p and standard error s = \sqrt{\frac{p(1 - p)}{n}}

In this problem:

  • 1,190 adults were asked, hence n = 1190
  • In fact 62% of all adults favor balancing the budget over cutting taxes, hence p = 0.62.

The mean and the standard error are given by:

\mu = p = 0.62

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.62(0.38)}{1190}} = 0.0141

The probability of a sample proportion of 0.59 or less is the <u>p-value of Z when X = 0.59</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.59 - 0.62}{0.0141}

Z = -2.13

Z = -2.13 has a p-value of 0.0166.

0.0166 = 1.66% probability of a sample proportion of 0.59 or less.

You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213

7 0
2 years ago
There are 84 boys in a senior class of 146 students. find the ratio of boys to girls. (note: if you know the total number of stu
vladimir1956 [14]
84 to 62. You have to subtract 146-84 to get the number of girls from the class.
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Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

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