Ask question

Ask question

All categories

2 years ago

10

Epd445 was allegedly caught texting 57 minors but 21 of them turned out to be of age. What is the total amount of minors he was

allegedly caught texting with?

2 answers:

qaws [65]2 years ago

5 0

Answer:

He was caught texting 36 minors.

ZanzabumX [31]2 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

A clockwise rotation of 90 degrees is equivalent to a counter clockwise rotation of how many degrees?

WARRIOR [948]

Equivalent to 180 degrees. 90 degrees clockwise +90 degrees

5 0

2 years ago

Read 2 more answers

Solve for c, 3ab-2bc=12

Troyanec [42]

-2bc=12-3ab

c=(3ab-12)/(2b)

6 0

2 years ago

The graph shown is a translation of the graph of f(x)=x^2. Write the function in vertex form.

Gnesinka [82]

$\sf \longrightarrow \: f(x) = {x}^{2}$

Write the parent function in the standard form I.e.

$\boxed{ \tt \:y =a(x - h) \times 2 + k }$

Where,

a = 1
h = 0
k = 0

$\sf \longrightarrow \:y= 1(x - 0)^{2} \times 2 + 0$

$\sf \longrightarrow \: y = (x - 0) ^{2} \times 2 + 0$

$\sf \longrightarrow \: y = {x}^{2} \times 2$

$\sf \longrightarrow \: y = 2{x}^{2}$

4 0

2 years ago

Please help!! giving brainliest !!!

ryzh [129]

Answer:

vertical angle theorem

Step-by-step explanation:

angles that are opposite of each other and formed by two intersecting straight lines, are congruent.

3 0

2 years ago

A computer chess game and a human chess champion are evenly matched. They play twelve games. Find probabilities for the followin

sleet_krkn [62]

Answer:

The probability that they each win six games is 0.225.

Step-by-step explanation:

Given : A computer chess game and a human chess champion are evenly matched. They play twelve games.

To find : The probability that they each win six games?

Solution :

Applying binomial distribution,

Here n=12 and p=0.5

$P(X=k)=\frac{n!}{k!(n-k)!}\times p^k\times (1-p)^{n-k}$

The probability that they each win six games is k=6.

$P(X=6)=\frac{12!}{6!(12-6)!}\times 0.5^6\times (1-0.5)^{12-6}$

$P(X=6)=\frac{12\times 11\times 10\times 9\times 8\times 7\times 6!}{6\times 5\times 4\times 3\times 2\times 6!}\times 0.015625\times 0.015625$

$P(X=6)=11\times 2\times 3\times 2\times 7\times 0.015625\times 0.015625$

$P(X=6)=0.225$

Therefore, The probability that they each win six games is 0.225.

3 0

2 years ago