Question

(a) the temperature on a warm summer day is 87 °f. what is the temperature in °c? (b) many scientific data are reported at 25 °c. what is this temperature in kelvins and in degrees fahrenheit? (c) suppose that a recipe calls for an oven temperature of 400 °f. convert this temperature to degrees celsius and to kelvins. (d) liquid nitrogen boils at 77 k. convert this temperature to degrees fahrenheit and to degrees celsius.

Answer 1

a. T = 87 F0

Temperature can be converted to celcius as follows:

F = (9 /5) C + 32

87 = (9 /5) C + 32

C = 30.55 C0

b. T = 25 C0

Temperature can be converted to kelvin as follows:

K = C + 273.15

= 30.55 + 273.15 = 303.7 K

F = (9 /5) C + 32

F = (9 /5) (25) + 32 = 77 F

c. T = 400 F

400 = (9 /5) C + 32

C = 204.44 C0

K = C + 273.15

K = 204.44 + 273.15 = 477.59 K

d . T = 77 K

77 K = C + 273.15

C = - 196.15 C0

F = (9 /5) C + 32

F = (9 /5) (- 196.15) + 32 = -321.07 F

Answer 2

Answer :

(a) The temperature in degree Celsius is, $30.5^oC$

(b) The temperature in Kelvin and in degree Fahrenheit is, 298K and $77^oF$ respectively.

(c) The temperature in degree Celsius and Kelvin is, $204.4^oC$ and 477.4 K respectively.

(d) The temperature in degree Fahrenheit and Celsius is, $-320.8^oF$ and $-196^oC$ respectively.

Explanation :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

$^oC=(^oF-32)\times \frac{5}{9}$

where,

$^oF$ = temperature in Fahrenheit  

$^oC$ = temperature in centigrade

The conversion used for the temperature from degree Celsius to Kelvin is:

$K=273+^oC$

where,

$K$ = temperature in Kelvin

$^oC$ = temperature in centigrade

(a) As we are given the temperature in Fahrenheit is, $87^oF$

Now we have to determine the temperature in degree Celsius.

$^oC=(^oF-32)\times \frac{5}{9}$

$^oC=(87^oF-32)\times \frac{5}{9}$

$^oC=30.5$

(b) As we are given the temperature in degree Celsius is, $25^oC$

Now we have to determine the temperature in Kelvin.

$K=273+^oC$

$K=273+25$

$K=298$

Now we have to determine the temperature in degree Fahrenheit.

$^oC=(^oF-32)\times \frac{5}{9}$

$25^oC=(^oF-32)\times \frac{5}{9}$

$^oF=77$

(c) As we are given the temperature in Fahrenheit is, $400^oF$

Now we have to determine the temperature in degree Celsius.

$^oC=(^oF-32)\times \frac{5}{9}$

$^oC=(400^oF-32)\times \frac{5}{9}$

$^oC=204.4$

Now we have to determine the temperature in Kelvin.

$K=273+^oC$

$K=273+204.4$

$K=477.4$

(d) As we are given the temperature in Kelvin, 77 K

Now we have to determine the temperature in degree Celsius.

$K=273+^oC$

$77=273+^oC$

$^oC=-196$

Now we have to determine the temperature in degree Fahrenheit.

$^oC=(^oF-32)\times \frac{5}{9}$

$-196^oC=(^oF-32)\times \frac{5}{9}$

$^oF=-320.8$