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Novay_Z [31]
4 years ago
5

What is the number of moles in 526 L O2 at STP?

Chemistry
2 answers:
NemiM [27]4 years ago
4 0

Answer: The correct answer is : 23.5 mol of O2 .

At STP ( Standard Temperature and potential ) 1 mole of gas has 22.4 L of volume .The follow can be expressed as :

Mole = \frac{given volume in L}{22.4 L }  * 1 mol

Given volume of O2 gas = 526 L

Plugging value in the formula :

Mole = \frac{526 L}{22.4 L} * 1 mol

Mole of O2 gas at STP = 23.5 mol

Katena32 [7]4 years ago
3 0
526 L O2 x 1 mol O2 / 22.4 L = 23.5 mol O2
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The taste of sour milk is lactic acid. What is the molecular formula for lactic acid if the percent composition is 40.00% C, 6.7
Svetradugi [14.3K]

Answer:

C3H6O3

Explanation:

To find the emperical of the compound,you divide the percentage composition of each element by it's molar mass(C=12, H=1, O=16).

For C,40/12=3.33. For H,6.71/1=6.71

For O,53.19/16=3.33.

Then divide everything by the smallest value which is 3.33

For C,3.33/3.33=1. For H,6.71/3.33=~2.

For O,3.33/3.33=1.

Emperical formula=CH2O

Molecular formula=(CH2O)n=90

(12+2*1+16)n=90

30n=90, n=3

molecular formula=(CH2O)3

molecular formula of lactic acid=C3H6O3.

4 0
4 years ago
Burning biofuels releases co2 into the atmosphere, contributing to global warming. however, this is at least partially offset by
castortr0y [4]
Photosynthesis in green plants during which CO2 is absorbed to form glucose
3 0
3 years ago
Convert 0.30 m to mm.
scoundrel [369]

Answer:

0.3 Meters = 300 Millimeters

Explanation:

Multiply the length value by 1000

Hopefully, this helps! :D

7 0
3 years ago
A solution of acetic acid, CH3CO2H(aq), is at equilibrium. How would the
umka21 [38]

Answer:

52

Explanation:

7 0
3 years ago
Hydrogen sulfide decomposes according to the following reaction, for which Kc = 9.30 10-8 at 700°C. 2 H2S(g) 2 H2(g) + S2(g) If
Vikentia [17]

Answer:

The equilibrium concentration of hydrogen gas is 0.0010 M.

Explanation:

The equilibrium constant of the reaction = K_c=9.30\times 10^{-8}

Moles of hydrogen sulfide = 0.31 mol

Volume of the container = 4.1 L

[concentration]=\frac{moles}{volume (L)}

[H_2S]=\frac{0.31 mol}{4.1 L}=0.076 M

2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

Initially

0.076 M

At equilibrium

(0.076-2x)                         2x     x

The expression of an equilibrium constant :

K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}

9.30\times 10^{-8}=\frac{(2x)^2\times x}{(0.076-x)^2}

Solving for x:

x = 0.00051

The equilibrium concentration of hydrogen gas:

[H_2]=2x=2\times 0.00051 M=0.0010 M

4 0
4 years ago
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