Explanation:
The given data is as follows.
Mass of apple sauce mixture = 454 kg
Heat added (Q) = 121300 kJ
Heat capacity (
) of apple sauce at
= 4.0177
So, Heat given by heat exchanger = heat taken by apple sauce
Q = ![mC_{p} \Delta T](https://tex.z-dn.net/?f=mC_%7Bp%7D%20%5CDelta%20T)
or, Q =
Putting the given values into the above formula as follows.
Q =
121300 kJ = ![454 kg \times 4.0177 kJ/kg^{o}C \times (T_{f} - 10)](https://tex.z-dn.net/?f=454%20kg%20%5Ctimes%204.0177%20kJ%2Fkg%5E%7Bo%7DC%20%5Ctimes%20%28T_%7Bf%7D%20-%2010%29)
= ![76.5^{o}C](https://tex.z-dn.net/?f=76.5%5E%7Bo%7DC)
Thus, we can conclude that outlet temperature of the apple sauce is
.
Answer:
1.5x 10^24
Explanation:
for every 1 mol there are 6.02 x 10^23 molecules
2.5 mol x 6.02 x 10^23
-----------------
1 mol
Answer:try to make a good pic please I have ideas about the topic