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4 years ago

Newton's Second Law of Motion states

Physics

1 answer:

EleoNora [17]4 years ago

6 0

Newton's second law of motion states that

D. the force acting on a body equals the rate of change of momentum

Explanation:

Newton's second law of motion states that the force acting on a body is equal to the product between the mass of the body and its acceleration. Mathematically:

$F=ma$

where

F is the force

m is the mass

a is the acceleration

We can re-write the acceleration as the rate of change of the velocity:

$a=\frac{\Delta v}{\Delta t}$

So we can re-write the equation as

$F=\frac{m\Delta v}{\Delta t}$

However, the term $m\Delta v$ represents the change in momentum of the body, $\Delta p$ (assuming its mass to be constant). Therefore, we can further rewrite the equation as

$F=\frac{\Delta p}{\Delta t}$

which means that the force acting on a body equals the rate of change of momentum (option D).

Learn more about Newton's second law:

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?a wire is stretched 30% what is the percentage change in resistance

Marat540 [252]

Answer:

The percentage change in resistance of the wire is 69%.

Explanation:

Resistance of a wire can be determined by,

R = (ρl) ÷ A

Where R is its resistance, l is the length of the wire, A its cross sectional area and ρ its resistivity.

When the wire is stretched, its length and area changes but its volume and resistivity remains constant.

$l_{o}$ = 1.3l, and $A_{o}$ = $\frac{A}{1.3}$

So that;

$R_{o}$ = (ρ $l_{o}$ ) ÷ $A_{o}$ = (ρ × 1.3l) ÷ ( $\frac{A}{1.3}$ )

= (1.3lρ) ÷ ( $\frac{A}{1.3}$ )

= $(1.3)^{2}$ × [(ρl) ÷ A]

= 1.69R (∵ R = (ρl) ÷ A)

$R_{o}$ = 1.69R

Where $R_{o}$ is the new resistance, $l_{o}$ is the new length, and $A_{o}$ is the new area after stretching the wire.

The change in resistance of the wire = $R_{o}$ - R

= 1.69R - 1R

= 0.69R

The percentage change in resistance = $\frac{0.69R}{R}$ × 100

= 0.69 × 100

= 69%

The percentage change in resistance of the wire is 69%.

3 0

3 years ago

En una práctica un beisbolista lanza verticalmente la bola con una velocidad de 12m/s en dirección ascendente. ¿Cuál será la alt

fgiga [73]

Answer:

Thus, the maximum height is 7.35 m.

Explanation:

initial velocity, u = 12 m/s

acceleration due to gravity, g = 9.8 m/s^2

Velocity at maximum height, v = 0 m/s

Let the maximum height is h.

Use third equation of motion

$v^{2}=u^{2}-2 g h\\0 = 12\times 12 - 2 \times 9.8\times h\\h =7.35 m$

8 0

3 years ago

Gravity is affected by

mrs_skeptik [129]

Gravity is affected by mass and distance

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3 years ago

A bicycle has wheels of 0.8 m diameter. The bicyclist accelerates from rest with constant acceleration to 22 km/h in 11.6 s. Wha

larisa [96]

Answer:

α = 1.32 rad/s²

Explanation:

given,

diameter of the bicycle = 0.8 m

radius of the bicycle = 0.4 m

initial speed of the bicyclist,u = 0 m/s

final speed of the bicyclist,v = 22 Km/h = 22 x 0.278

= 6.12 m/s

time,t = 11.6 s

acceleration = $\dfrac{v-u}{t}$

= $\dfrac{6.12-0}{11.6}$

=0.53 m/s²

we know,

a = α r

$\alpha=\dfrac{a}{r}$

$\alpha=\dfrac{0.53}{0.4}$

α = 1.32 rad/s²

the angular acceleration of the wheels is equal to α = 1.32 rad/s²

7 0

3 years ago

The smallness of the critical angle θc for diamond means that light is easily "trapped" within a diamond and eventually emerges

hoa [83]

Answer:

26.6°

Explanation:

refractive index of diamond, n = 2.23

When a ray of light passes from denser medium to the rarer medium and refracts at an angle of 90 degree from the normal of the surface, such angle of incidence in the denser medium is called the critical angle.

By the Snell's law

$\frac{Sini}{Sin r }= n$

For critical angle, angle of incidence is critical angle, i = θc and angle of refraction, r = 90

So,

Sin θc / Sin 90 = 1 / 2.23

Sin θc = 0.448

θc = 26.6°

Thus, the critical angle is 26.6°.

3 0

3 years ago