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liq [111]
3 years ago
15

En una práctica un beisbolista lanza verticalmente la bola con una velocidad de 12m/s en dirección ascendente. ¿Cuál será la alt

ura máxima que alcanza la pelota?
Physics
1 answer:
fgiga [73]3 years ago
8 0

Answer:

Thus, the maximum height is 7.35 m.

Explanation:

initial velocity, u = 12 m/s

acceleration due to gravity, g = 9.8 m/s^2

Velocity at maximum height, v = 0 m/s

Let the maximum height is h.

Use third equation of motion

v^{2}=u^{2}-2 g h\\0 = 12\times 12 - 2 \times 9.8\times h\\h =7.35  m

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Answer:

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Explanation:

Solution:

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Since, K is the constant for a particular spring, we need to change the mass of the cart to change the time period.

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