The electron charge is equal to

. The atomic nucleus of the problem has a charge of

. The distance between the nucleus and the electron is

, so we can calculate the electrostatic (Coulomb) force between the two:


which is attractive, since the two charges have opposite sign.
Answer:
The induced emf in the coil is 170 volt and its direction is clockwise direction.
Explanation:
Given that,
Number of turns of a coil, N = 50
Initial area, 
Final area, 
Time, t = 0.1 s
The magnetic field points into the page and has a strength of 1.36 T.
We need to find the magnitude and direction of the average value of the induced emf. Due to change in area of the coil and emf will be induced in it. The induced emf is given by :
So, the induced emf in the coil is 170 volt and its direction is clockwise direction. Hence, this is the required solution.
Answer: Light waves move faster than sound waves, which are longitudinal.
Light waves can also travel through space.
Sound waves, being longitudinal, are slower than light waves, and do not travel through space.
Answer:
Incomplete question
This is the complete question
The Earth possesses an electric field of (average) magnitude 150 near its surface. The field points radially inward. Calculate the net electric flux outward through a spherical surface surrounding, and just beyond, the Earth's surface.
Explanation:
Given that,
Electric field is 150N/C inward
i.e E = - 150 i
Then, electric flux (Φ) is given as
Φ=∮E.dA
Surface area of a sphere is
A=4πr²
dA=8πr dr
The area is outwardly i.e
dA=-8πr dr i
Φ=∮E.dA
Φ=∮-150 i • 8πr i dr from 0 to R
Φ= -1200π∮rdr. From 0 to R
Φ= -1200π r²/2. From 0 to R
Φ= -600π [R² -0²]
Φ= -600πR²
Where R is radius of earth which is 6,400,000m
Φ= -600πR²
Φ= -600π(6400000)²
Φ= -7.72×10^16 Nm²/C