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kenny6666 [7]
4 years ago
15

Use the coordinates to find the length of each side of the rectangle. Then find the perimeter. L(3,3), M(3,5), N(7,5), P(7,3)

Mathematics
2 answers:
larisa86 [58]4 years ago
5 0
Length of legs:2,2,4,4, p=12
zepelin [54]4 years ago
5 0
Length of legs:2,2,4,4, p=12
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Which sets of ratios are a proportion? (Choose all that apply) *
vladimir1956 [14]

Answer:

<h2>Sets of Ratios that are Proportion</h2>

3/11 and 17/6

<h3>12/7 and 36/21</h3>

60/55 and 7/25

7/6 and 52/48

<h3>4/10 and 8/20</h3>

<h3>Solution:</h3>

> 12/7 and 36/21

\frac{12}{7}  =  \frac{36}{21}  \\ 12(21) = 36(7) \\ 252 = 252

> 4/10 and 8/20

\frac{4}{10}  =  \frac{8}{20}  \\ 4(20)  = 8(10) \\ 80 = 80

5 0
3 years ago
Find the most important variable in the problem.
lozanna [386]

Answer:

a

Step-by-step explanation:

4 0
3 years ago
A banner needs to be enlarged from its original format. The dimensions of the original are 4 cm tall by 25 cm wide.The enlarged
Alex_Xolod [135]
Hope this helps you!

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D
Makovka662 [10]

Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

=2(x^2-4)^4(4x-5)^3(28x^2-57)

7 0
3 years ago
Find the z-scores that bound the middle 74% of the area under the standard normal curve.
aniked [119]

Since 74% of the middle area is bounded, this means that there is 13% on the left side, and another 13% on the right side.

P (left) = 0.13

P (right ) = 1 - 0.13 = 0.87

 

At this P values, the z scores are approximately:

z score (left) = -2.22

<span>z score (right) = 1.13</span>

5 0
3 years ago
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