Consider the first five steps of the derivation of The Quadratic function

Mathematics

1 answer:

Burka [1]3 years ago

7 0

Answer:

Step-by-step explanation:

pick like terms

x² + b²/4a² = -c / a + b²/4a²

b²/4a² = (b/2a)²

x² + (b/2a)² = -c/a + (b/2a)²

(x + b/2a)² = -c/a + (b/2a)² = -c / a + b²/4a² = (-4ac+ b²)/4a²

(x + b/2a)² = (-4ac+ b²)/4a²

square root both sides

√{(x + b/2a)²} = √{(-4ac+ b²)/4a²}

x + b/2a = √(-4ac+ b²) / √(4a²) = √(-4ac+ b²) / 2a = √( b²-4ac) / 2a

x + b/2a = √( b²-4ac) / 2a

subtract b/2a from both sides

x + b/2a -b/2a = {√( b²-4ac) / 2a } -b/2a

x = -b/2a + {√( b²-4ac) / 2a }

the l.c.m is the same

x = {-b±√( b²-4ac)}/2a

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I need help pls I need it for school thank uu

Effectus [21]

C is the answer for sure I think

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2 years ago

PLZ HELP ASAP DIVIDE LINE SEGMENTS

Yuri [45]

A (4,8) and b (7,2) and let c (x,y)

A , B and C are col-linear ⇒⇒⇒ ∴ slope of AB = slope of BC
slope of AB = (2-8)/(7-4) = -2
slope of BC = (y-2)/(x-7)
∴ (y-2)/(x-7) = -2
∴ (y-2) = -2 (x-7) ⇒⇒⇒ equation (1)

The distance between two points (x₁,y₁),(x₂,y₂) = d
$d = \sqrt{ (x2-x1)^{2} + (y2-y1)^{2} }$

The ratio of AB : BC = 3:2
AB/BC = 3/2
∴ 2 AB = 3 BC
$2 * \sqrt{ (7-4)^{2} + (2-8)^{2} }$ = $3* \sqrt{ (x-7)^{2} +(y-2)^{2} }$
eliminating the roots by squaring the two side and simplifying the equation
∴ 4 * 45 = (x-7)² + (y-2)² ⇒⇒⇒ equation (2)
substitute by (y-2) from equation (1) at equation (2)
4 * 45 = 5 (x-7)²
solve for x
∴ x = 9 or x = 5
∴ y = -2 or y = 6

The point will be (9,-2) or (5,6)
the point (5,6) will be rejected because it is between A and B

So, the point C = (9,-2)

See the attached figure for more explanations