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3 years ago

I will mark u brainliest

Mathematics

1 answer:

shutvik [7]3 years ago

8 0

Answer:

2a...true

2b...false

2c....false

2d....false because you are supposed to add and not multiply

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Anyone? Help ? Plz?❤️❤️

vesna_86 [32]

Answer:

C a dilation will always produce similar figures

Step-by-step explanation:

If the scale factor is >1 then the figure will get larger

< 1 the figure gets smaller

=1 it is congruent

We can rotate the figure but that is not by dilation. dilation does not change the orientation, unless the scale factor is negative( which is a reflection)

3 0

3 years ago

Solve the following: 3.12 × 1,000 = _____.

torisob [31]

Answer:

60000000.00

Step-by-step explanation:

hgfgjffhvffjfujcdhbcfvjnbcccdsd

8 0

3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago

What is an example of a one step equation that would use multiplication

velikii [3]

Answer:

here is a photo

5 0

2 years ago

Use the quadratic function f(x) = 2x^2 + 4x - 15. Find any x intercepts.

8_murik_8 [283]

So for this function we will be using the quadratic formula, which is $x=\frac{-b+\sqrt{b^2-4ac}}{2a},\frac{-b-\sqrt{b^2-4ac}}{2a}$ , to solve. a = x^2 coefficient, b = x coefficient, and c = constant. Using our equation, we can solve for the zeros (x-intercepts) as such:

$x=\frac{-4+\sqrt{4^2-4*2*(-15)}}{2*2},\frac{-4-\sqrt{4^2-4*2*(-15)}}{2*2}\\ \\ x=\frac{-4+\sqrt{16-(-120)}}{4},\frac{-4-\sqrt{16-(-120)}}{4}\\ \\ x=\frac{-4+\sqrt{136}}{4},\frac{-4-\sqrt{136}}{4}\\ \\ x=1.92,-3.92$

In short, your x-intercepts (rounded to the hundredths) are (1.92,0) and (-3.92,0).

6 0

3 years ago