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3 years ago

Using 50 gal per minute pumps how long will it take to fill a basement that is 16 inched in depth

2 answers:

4 0

Those TWO pumps together work at a rate 100 gallons per minute.

You have basement dimensions, but to get volume as gallons, you need to know:
This is wrong: 231 cubic feet = 1 gallon

Know these: 231 cubic inches = 1 gallon, 12 inches = 1 foot

, cubic feet, the volume of water in the basement - which seems to be given in two sections.

You would use a uniform rates formula like RT=V for rate, time, volume.
You would use it as T=V/R.

irga5000 [103]3 years ago

3 0

For a total of 14681.9 gallons. At 50 gallons per minute it will take 294 minutes which is about 5 hours and hence with 2 pumps about 2.5 hours.

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Which one don’t lie

Marat540 [252]

Answer:

lol the answer is B

5 0

3 years ago

Read 2 more answers

Help pls ty in advance

svetoff [14.1K]

$\bold{\huge{\underline{ Solution\: 2 }}}$

The name of the circle is IJKL
The name of central Angle
$\sf{\underline{= {\angle} IHJ }}$
The name of the secant = KL

${\bigstar}$ Circle :- It is a round figures, which has no end points.

${\bigstar}$ Central angle :- It the angle ,which lie in the middle of the circle.

Here, H is the mid point of the circle .So, Angle IHJ is the central angle.

${\bigstar}$ Secant :- A line drawn in circle in such a way that it intersect the circle from two distinct points. Then, It is called secant .

Here, KL is the line which acts as a secant because it intersect the circle from point K and point L.

$\bold{\huge{\underline{ Solution\: 3 }}}$

Semicircle = FGH and FIH
Minor Arc :- FG or GH
Major Arc :- FHG or GFH

${\bigstar}$ Semicircle :- Semicircle is nothing but the half of the circle.

Here, In second diagram 

FGH and FIH are acting as two semicircles which simulatineously forming one circle.

${\bigstar}$ Minor Arc :- Minor Arc is nothing but the smaller arc of the circle and it is always smaller than the half of the circle that is semicircle.

Here, 

FG or GH are the minor arc of the given circle.

${\bigstar}$ Major Arc :- Major Arc is nothing but the largest arc of the circle and it is always larger than the half of the circle that is semicircle.

Here, 

FHG or GFH is the major arc as it is larger than the semicircle of the given circle .

7 0

2 years ago

What is the distance between -10 and 5 on the number line?

stiks02 [169]

Answer:

the distance is 15

Step-by-step explanation:

because if we take away the negative on the -10 and make it positive 10 and add 5 it would be 15 spaces

8 0

3 years ago

She has enough bricks to cover 60 square feet. She wants the length of the patio to be 4 feet longer than the width. What dimens

Natalija [7]

Answer:

10 feet length and 6 feet width.

Step-by-step explanation:

If the total area of the patio is going to be equal to 60 square feet and the length is going to be 4 feet longer than the width, the dimensions that she should use for the patio are 10 feet for the length and 6 feet for the width which will equal to 60 square feet in total.

I hope this answer helps.

3 0

3 years ago

Determine which equation is belongs to the graph of the limacon curve below.

JulsSmile [24]

Answer: Option C.

Step-by-step explanation:

We have functions of r(θ)

In our graph, we can see that the minimum value of r is when θ = 0°, and the maximum value is when θ = 180°.

We also know that the graph is in the square (-5, 5)x(-5, 5) and you can see that the maximum radius is almost less than 5.

Then let's analyze the options:

A) r = 3 - 2*cos(θ)

the maximum is at the right angle, but the maximum is:

r = 3 -2*(-1) = 5, so this maximum value is bigger than the one in the graph.

B) r = 3 - sin(θ)

For the sin functions, the maximum and minimum do not correspond with the values i write earlier, so we can discard this option.

C) r = 3 - cos(θ)

The maximum is: r = 3 - (-1) = 4, so this may be the correct answer.

the minimum is r = 3 - 1 = 2,

this is a possible equation for our circle.

D) r = 2 - 2*cos(θ)

Here, when θ = 0, we have: r = 2 - 2*1 = 0, but in the graph we can see that the radius is not 0 when θ = 0, so we can discard this option.

So the only option that makes sense is option C.

8 0

3 years ago