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dangina [55]
3 years ago
15

Andy bought 3 bags of a new birdseed mixture on sale. The birds in his yard like it so well that his friend Mike bought 5 bags.

Together they spent $13.20. How much does each bag cost? _____
Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0

Answer:

$1.65.

Step-by-step explanation:

Let x represent cost of each bag of birdseed.

We have been given that Andy bought 3 bags of a new birdseed mixture on sale. Cost of 3 bags of birdseed would be 3x.

The birds in his yard like it so well that his friend Mike bought 5 bags. Cost of 3 bags of birdseed would be 5x.

We are also told that together they spent $13.20, we can represent this information in an equation as:

3x+5x=\$13.20

8x=\$13.20

\frac{8x}{8}=\frac{\$13.20}{8}

x=\$1.65

Therefore, the cost of each bag of birdseed would be $1.65.

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Shilpa bought 30 T-shirt at a clothing store. 20% of the t-shirt were blue and 1/2 of the t-shirts were black. Howmany of the t-
k0ka [10]
The number of T-shirt bought by Shilpa from a clothing store = 30
Percentage of T-shirt that were blue = 20%
Then Number of T-shirt that were blue in color = (20/100) * 30
                                                                           = 2 * 3
                                                                           = 6
Number of T-shirts that were black in color = (1/2) * 30
                                                                     = 15
Then
The total number of T-shirts that were black and blue = (15 + 6)
                                                                                     = 21
Then
The total number of T-shirts that were neither black nor blue = 30 - 21
                                                                                                 = 9
So the number of T-shirts that were neither black nor blue was 9.
8 0
3 years ago
Listed below are the weights in pounds of 11 players randomly selected from the roster of the Seattle Sea-hawks when they won Su
weeeeeb [17]

Answer:

No. These measures show a thinner team of NFL players according to the mean, variance, standard deviation, and quartiles.

Step-by-step explanation:

1) The measures of variation, namely The Range, Variance, Quartiles, Interquartiles, Sum of Squares, etc. shows us how the data are dispersed.

The Range Δ is calculated:

\Delta =305-189=116 Maximum value - Minimum value for weight

Mean:

\bar{x}=\frac{189+254+235+225+190+305+202+190+252+305}{11}\approx 231.09 \:pounds

Variance:

s^{2}=\frac{\sum_{i=1}^{n} (x_i-\bar{x})^{2}}{n-1}\Rightarrow s=1923.69\\

The Standard Deviation of the sample

s=\sqrt{s^{^{2}}}\Rightarrow s\approx 43.86\\

2) Since there is no preceding exercise, the comparison was made to a recent study in which a NFL player average weight is about 245 pounds (average),

Since 25% of this list are player whose weight is 192.5 lbs and 50% (2nd Quartile) =225 lbs , finally only at the 3rd Quartile we have players above the regular NFL average with 253. This, added with the other data, allow us to say that this list is not a typical of all NFL players.

4 0
3 years ago
A solid lies between planes perpendicular to the​ x-axis at x = -2 and x = 2. The​ cross-sections perpendicular to the​ x-axis b
icang [17]

Answer:

V = 128π/3 vu

Step-by-step explanation:

we have that: f(x)₁ = √(4 - x²);  f(x)₂ = -√(4 - x²)

knowing that the volume of a solid is  V=πR²h, where R² (f(x)₁-f(x)₂) and h=dx, then

dV=π(√(4 - x²)+√(4 - x²))²dx;  =π(2√(4 - x²))²dx ⇒

dV= 4π(4-x²)dx , Integrating in both sides

∫dv=4π∫(4-x²)dx , we take ∫(4-x²)dx and we solve

4∫dx-∫x²dx = 4x-(x³/3) evaluated -2≤x≤2 or too 2 (0≤x≤2) , also

∫dv=8π∫(4-x²)dx evaluated 0≤x≤2

V=8π(4x-(x³/3)) = 8π(4.2-(2³/3)) = 8π(8-(8/3)) =(8π/3)(24-8) ⇒

V = 128π/3 vu

8 0
3 years ago
Expressions cannot _____.
Gwar [14]
Expressions cannot <u>be solved.
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8 0
3 years ago
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guapka [62]

Answer:

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Step-by-step explanation:

As The volume of cube =the cube(^3) of the sides.

7 0
3 years ago
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