Let the score on her seventh test be "x".
SO,

∴ He must get 104% on his seventh test to get an average score of 90%
Answer:
16/29
Step-by-step explanation:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(basketball or baseball) = P(basketball) + P(baseball) - P(both)
= (13/29) + (7/29) - (4/29)
= 16/29
The probability that a randomly chosen student plays either sport is 16/29.
D -2, 4 is in the second quadrant because the -x brings it to the left side and the positive 4 puts it in the upper of the left side which is the second quadrant
3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions