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2 years ago

Please do statement reasoning for the image!

Mathematics

1 answer:

SCORPION-xisa [38]2 years ago

3 0

Answer:

Ac=cd & ab=bd +common side so abc=dbc

same for ehf and ghf but difference in common right angle.

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Which describes how to calculate the range of this data set?

ELEN [110]

Answer:

B) Subtract 12-4 to calculate the range of this data set

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3 years ago

Simplify the expression:<br> -12 - 4x + 9 + -10 + 8x

Ann [662]

Answer:

Step-by-step explanation:

4x-13

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3 years ago

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Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

8 0

3 years ago

There are 7 girls on a bus. each girl has 7 backpacks. each backpack has 7 big cats. each big cat has 7 little cats. how many le

Vera_Pavlovna [14]

7 girls on a bus, each has two legs. 7 * 2 = 14.

Each girl has 7 backpacks. So 7 * 7 = 49.

49 * 7 = 343 cats in total

343 * 4 = 1,372 cat legs.

343 * 7 = 2401 small cats

2401 * 4 = 9,604 cat legs

14 + 1,372 + 2,401, + 9,604 = 10,990 legs in total

6 0

3 years ago

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Every number other than 0 has a multiplicative inverse.

Gala2k [10]

Answer:

A multiplicative inverse of a real number x is a real number y such that xy = 1. ... ((NOT GOOGLING DEF))

Step-by-step explanation:

"For every real number x, if x 0, then there is a real number y such that xy = 1.”

3 0

3 years ago