The equation of a linear function: y = mx + b
x = y - 3 → y - 3 = x <em>add 3 to both sides</em>
y = x + 3 <em>it's a linear function!</em>
y = x³ + 2 NOT, because we have x³
y = 6x² NOT, because we have x²
y = 2/(3x) NOT, because x is in denominator.
Answer:
-1/2
Step-by-step explanation:
Pick 2 points on the line, that are real whole numbers. I used (-3,-3) and (-1,-4)
Calculate the slope using rise over run. -4-(-3)=-1
-3-(-1)=2
Or, after choosing the dots, you can make a triangle
Considering that the given derivative is:
dy
----- = (x - 6)^ (1/2) ,
dx
y is the function whose derivative is (x - 6)^ (1/2).
Given that the derivative of (x - 6) ^ (3/2) is (3/2)* (x - 6)^ (1/2), you have that the function searched is y = (2/3) ( x - 6) ^ (3/2) plus a constant.
You can prove that dy / dx is (2/3)*(3/2) (x - 6) ^ (3/2) = (x - 6)^ (1/2).
Answer: y = (2/3) (x - 6)^(3/2).+ constant
You need to isolate x.
Divide by 2 on both sides.
2x/2 > 7/2
You don't need to flip the > sign in this case.
x>7/2