$y=4x-4\\\\\text{Substitute the coordinates of each points to the equation}\\\text{and check the equality.}\\\\1.\ (0,\ 4)\to x=0,\ y=4\\\\4=4(0)-4\\4=0-4\\4=-4\qquad\bold{FALSE}\\\\2.\ (0,\ -4)\to x=0,\ y=-4\\\\-4=4(0)-4\\-4=0-4\\-4=-4\qquad\bold{TRUE}\\\\3.\ (-4,\ 0)\to x=-4,\ y=0\\\\0=4(-4)-4\\0=-16-4\\0=-20\qquad\bold{FALSE}\\\\4.\ (4,\ 0)\to x=4,\ y=0\\\\0=4(4)-4\\0=16-4\\0=12\qquad\bold{FALSE}$

5 0

2 years ago

Determine the solution of the system. Show your work

Oxana [17]

First question:

1. Set equations equal to each other so 5x-9=2x+6
2. Put x's on one side so that 3x=15
3. Divide by 3 so that x=15
4. Substitute 15 in for x so that y=2(15)+6
5. Solve for y so that y=36
6. Thus the equations intersect at (15,36)

Second question:

1. Since for lines y=mx+b, and m=slope=3 you only need to write an equation with slope 3
2. y=3x+b, b can be any number

3 0

2 years ago

Basic algebra question I struggle with

maxonik [38]

Cross multiply
2x(3x-4) = 3(x+2)
5x - 8x = 3x + 6
-3x= 3x+6
x = 6
I think

5 0

2 years ago

Read 2 more answers

(Easy) For the following quadratic function, find the axis of symmetry, the vertex and the y-intercept. y = x^2 + 12x + 32

hammer [34]

Answer:

$y ( \times + 6) 2 - 4$