Answer:
6.58×10⁻¹⁸ J
Explanation:
Applying
E = kq²/r.................. Equation 1
Where E = potential energy, q = charge on each electron, r = distance between the electron, k = coulomb's constant.
From the question,
Given: r = 3.5×10⁻¹¹ m,
Constant: q = 1.6×10⁻¹⁹ C, k = 8.99×10⁹ Nm²/C²
Substitute these values into equation 1
E = (1.6×10⁻¹⁹)²(8.99×10⁹)/(3.5×10⁻¹¹)
E = 6.58×10⁻¹⁸ J
Your answer would be 0.20 Hz
