Samplce c becasue the [ercatage of the engery is less so less sound will go trough
Answer:
maximum speed of the block is 3.14 m/s
Explanation:
given data
mass = 1.70 kg
stretch in the spring = 0.2 m
time take by block to come to zero t = 0.2 s
solution
we know that Time period of oscillation (T) that is express as
T = 2t ......................1
put here value
T = 2 (0.2)
T = 0.4 s
so here time period is express as
T =
................2
here k is spring constant of the spring so put here value
0.4 =
here k will be
k = 419.02 N/m
so we use here conservation of energy that is
Maximum kinetic energy = Maximum spring potential energy ............3
(0.5) m v² = (0.5) k x²
here v is maximum speed block
so put here value and we get
(1.70) v² = (419.02) (0.2)²
v = 3.14 m/s
so maximum speed of the block is 3.14 m/s
Answer:
The range of angles is from 17.50° to 31.76°
Explanation:
The diffraction grid equation is as follows:

Clearing for 


where
is the angle,
is the order, in this case
,
is the wavelength, and
is defined as follows:

and since the resolution is 750 lines/mm wich is the same as 
will be:

wich is the distance between each line of the diffraction grating.
substituting the values for
and
:

And we need to find two angle values: one for when the wavelength is 400nm and one for when it is 700 nm. So we will get the angle range

and

The range of angles is from 17.50° to 31.76°
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