Answer: The slope of a line on a distance-time graph is- speed of the object.
The slope of a line on a graph refers to rate of change of variable that is presented on Y axis with respect to the variable that is presented on X axis.
For a distance time graph, distance is presented on Y axis and time on the X axis.
As we know that
Therefore, the slope of a line on a distance-time graph represents speed of the object.
Answer:
0.84 Ω
Explanation:
r = mean radius of the turn = 6.5 mm
n = number of turns of copper wire = 150
Total length of wire containing all the turns is given as
L = 2πnr
L = 2 (3.14)(150) (6.5)
L = 6123 mm
L = 6.123 m
d = diameter of the wire = 0.4 mm = 0.4 x 10⁻³ m
Area of cross-section of the wire is given as
A = (0.25) πd²
A = (0.25) (3.14) (0.4 x 10⁻³)²
A = 1.256 x 10⁻⁷ m²
ρ = resistivity of copper = 1.72 x 10⁻⁸ Ω-m
Resistance of the coil is given as
R = 0.84 Ω
Answer:
a
The radius is
b
The total charge is
c
The electric potential inside sphere is the same with that outside the sphere which implies that the electric potential is 832 V
d
The magnitude of the electric field is
e
The velocity is
Explanation:
From the question we are told that
The potential is
The radial distance from the sphere is
The potential at the radial distance is
The potential at the surface of the sphere is mathematically represented as
Where kQ is a constant what this means that the the charge Q and the coulomb constant do not change
This means that
Where is the radius of the sphere
and is the distance from that point where the second potential was measured to the center of the sphere which is mathematically represented as
Substituting this into the equation
Now substituting value
From the equation above
making Q the subject
k has a values of
Substituting into the equation
According to Gauss law the electric field from outside a sphere is taken to be an electric field from a point charge this mean that the potential outside a sphere is also taken as electric potential inside a sphere
The magnitude of a electric field from a sphere (point charge ) is mathematically represented as
Substituting values
According the the law of energy conservation
The electric potential energy at the point outside the surface where the second potential was measured(21 cm from the sphere surface) = The electric potential energy at the surface + The kinetic energy of the charge (electron) at that the surface
Generally Electric potential energy is mathematically represented as
Where is e is an electron
And Kinetic energy is mathematically represented as
From the statement above
But from the question we can deduce that the potential at the surface is zero
So the equation becomes
The charge an electron has a value
And the mass of an electron is
Making v the subject
Substituting value
Answer:
The final velocity is 8 m/s and its direction is along the positive x-axis
Explanation:
Given :
Mass, m₁ = 2000 g = 2 kg
Mass, m₂ = 4000 g = 4 kg
Initial velocity of mass m₁, v₁ = 24i m/s
Initial velocity of mass m₂, v₂ = 0
According to the problem, after collision the two masses are stick together and moving with same velocity, that is, .
Applying conservation of momentum,
Momentum before collision = Momentum after collision
Substitute the suitable values in the above equation.