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denpristay [2]
3 years ago
10

(5+10)/5 what’s a problem

Mathematics
1 answer:
maksim [4K]3 years ago
8 0

Answer:

3

Step-by-step explanation:

Follow the rules of PEMDAS

Parenthesis

Exponents

Multiplication/Division

Addition/Subtraction

Simplify what is inside the parenthesis

\frac{5+10}{5}

\frac{15}{5}

Divide

3.

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Find the area of a rectangle that is 16 3/5in. by 8 9/10
Alenkinab [10]
<h2>Greetings!</h2>

Answer:

Area is 147.74

Step-by-step explanation:

You need to recall that the equation for the area of a rectangle is:

Length * Width = area

So 16 3/5 * 8 9/10 = area

Rearrange so the whole numbers are being multiplied and the fractions are too:

We need to make the denominator same, this can be done by simply multiplying 3/5 by 2:

3/5 * 2 = 6/10

Now the two numbers can be written as 16.6 and 8.9.

Multiply both numbers by 10:

166 * 89 = 14774

Then divide this by 100 (two lots of division by 10)

14774 ÷ 1000 = 147.74

So the area of the rectangle is 147.74!


<h2>Hope this helps!</h2>
8 0
3 years ago
Math, please help! Will give brainliest.
natka813 [3]
This one is probably f(x)=2(4)^{x}
8 0
3 years ago
Given: cos θ=-4/5, sin x = -12/13, θ is in the third quadrant, 
USPshnik [31]

By definition of tangent,

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

Recall the double angle identities:

sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)

cos(2<em>θ</em>) = cos²(<em>θ</em>) - sin²(<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

where the latter equality follows from the Pythagorean identity, cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1. From this identity we can solve for the unknown value of sin(<em>θ</em>):

sin(<em>θ</em>) = ± √(1 - cos²(<em>θ</em>))

and the sign of sin(<em>θ</em>) is determined by the quadrant in which the angle terminates.

<em />

We're given that <em>θ</em> belongs to the third quadrant, for which both sin(<em>θ</em>) and cos(<em>θ</em>) are negative. So if cos(<em>θ</em>) = -4/5, we get

sin(<em>θ</em>) = - √(1 - (-4/5)²) = -3/5

Then

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

tan(2<em>θ</em>) = (2 sin(<em>θ</em>) cos(<em>θ</em>)) / (2 cos²(<em>θ</em>) - 1)

tan(2<em>θ</em>) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2<em>θ</em>) = 24/7

4 0
3 years ago
Which of the following best classifies a quadrilateral with coordinates A(2,6), B(5, 1), C(10, 4), and D(7,9)?
navik [9.2K]

Answer:

a rhombus

Step-by-step explanation:

If you graph the problem, you can see the shape of the quadrilateral. I attached a picture of a graph below. I hope this helped you!! Have a great rest of your day.

3 0
3 years ago
Gary deposited $20 in a savings account earning 10% interest, compound annually. to the nearest cent, how much will he have in 3
Strike441 [17]
<h3>Answer: $26.62 </h3>

============================

Work Shown:

P = 20 is the amount deposited

r = 0.10 is the decimal form of the 10% interest rate

n = 1 means we compound 1 time per year (annually)

t = 3 is the number of years

Plug those four values into the compound interest formula below

A = P*(1+r/n)^(n*t)

A = 20*(1+0.1/1)^(1*3)

A = 20*(1+0.1)^(3)

A = 20*(1.1)^(3)

A = 20*1.331

A = 26.62

5 0
3 years ago
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