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2 years ago

What is the right way to work this problem? (- -3 +12)

Mathematics

1 answer:

Anna007 [38]2 years ago

3 0

Answer:

Step-by-step explanation:

yes

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(2y + 9)(3y - 1) = 5y2 + 25y - 9

Vikki [24]

Answer:

y1= 0, y2= 5/3

Step-by-step explanation:

Remove the parentheses and multiply

then cancel the equal terms

collect the lie terms

move the variables to one side

divide both sides by two

split into possible cases

then solve the equation to get

y= 0 and

y= 5/3

7 0

2 years ago

Please help me *30 points*

sasho [114]

Answer:

number 1 is -1.5

number 2 is -2 1/6

Step-by-step explanation

7 0

3 years ago

Read 2 more answers

A soccer goalie kicks the soccer ball.The quadratic function y=-16t^2+48t gives the time t seconds when the soccer ball is at he

ipn [44]

I believe it is 1,536

3 0

2 years ago

Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which

alekssr [168]

Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

$V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3$

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

$0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L$

1.25 liters of oil are needed.

6 0

2 years ago

Pls answer 2 people or more

fredd [130]

I believe it’s B . Not 100 percent sure but yeah

6 0

2 years ago