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Natalija [7]
3 years ago
7

What is the right way to work this problem? (- -3 +12)

Mathematics
1 answer:
Anna007 [38]3 years ago
3 0

Answer:

15

Step-by-step explanation:

yes

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Fill in the blank to complete the equation. Then find quotion 5÷1/2
hichkok12 [17]
I'm not sure about the equation, but the quotient to 5 ÷ \frac{1}{2} = 10. 

"KEEP IT, CHANGE IT, FLIP IT."
This is applied to find the quotient, and once done, the answer is found to be 10.
5 0
3 years ago
amanda increased the amount of protein she eats evry day from 48 to 54 g by what percentage di amanda increas3 the amount of pro
sammy [17]

Answer:

the amount increased by approximatley 12%

Step-by-step explanation:

4 0
3 years ago
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Approximately how many square inches of space are blank?
ddd [48]

Answer:

blank area = 1.5π units²

Step-by-step explanation:

area of full circle = πr² = π6² = 36π units²

blank area = (15/360)(36π) = 1.5π units²

3 0
3 years ago
URGENT, PLEASE HELP! (3/5) -50 POINTS- !please no wrong answers for the points.! A) <img src="https://tex.z-dn.net/?f=y%20%3D%20
shtirl [24]

Answer:

B y = -1/2x + 7/2

Step-by-step explanation:

We know that it has a negative slope since the points go from the top left to the bottom right

We can eliminate A and D

The y intercept is where it crosses the y axis

It should cross somewhere between 2 and 4

C  has a y intercept of 9 which is too big

Lets verify with a point

x = -4

y = -4(-4)+9 = 16+9 = 25  (-4,25)  not even close to being near the points on the graph

checking B

y = -1/2 (-4) +7/2

  = 2 + 7/2 = 11/2 = 5.5  it seems  reasonable

5 0
3 years ago
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An object is acted upon by the forces F1=&lt;10​,6​,4&gt; and F2=&lt;0​,3​,9&gt;. Find the force F3 that must act on the object
murzikaleks [220]

\vec F_3=\langle x,y,z\rangle is a force vector such that

\vec F_1+\vec F_2+\vec F_3=\vec0

\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle

\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13

So the missing force is

\boxed{\vec F_3=\langle-10,-9,-13\rangle}

8 0
3 years ago
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