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Ber [7]
3 years ago
7

Kathy is standing directly between two tall buildings which are 100 feet apart. Her eye level is 5 feet above the ground. Kathy

looks up at the top of the taller building and the top of the shorter building with angles of 45 degrees and 38 degrees above the horizontal, respectively. What is the difference in height between the taller building and the shorter building, to the nearest foot?
Mathematics
1 answer:
Zinaida [17]3 years ago
4 0

 

 

Angle of taller building Tan 45° = opposite (height of the building)/ adjacent 50 feet (distance between Kathy and the taller building

Tan 45° = 1

Height of taller building from eye level = multiplying adjacent 50 feet * Angle (Tan 45°) 1 = 50 feet opposite

 

Angle of smaller building Tan 38° = 0.781

Height of smaller building from eye level = Angle * adjacent 50 feet = 39.06 feet

 

 

 

Difference of eye level from ground is 5 feet

Taller building height is 50 + 5

Total height of taller building is 55 feet.

Smaller building height is 39.06 + 5

Total height of smaller building is 44.06 feet

 

 

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A sample of 16 eggs yields a sample mean weight of 3.00 ounces and a sample standard deviation = 0.360 ounces, find the margin o
shusha [124]

Answer:

ME =1.753\frac{0.360}{\sqrt{16}}= 0.158

3-1.753\frac{0.360}{\sqrt{16}}=2.842    

3+1.753\frac{0.360}{\sqrt{16}}=3.158    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=3 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=0.360 represent the sample standard deviation

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=16-1=15

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,15)".And we see that t_{\alpha/2}=1.753

The margin of error is given by:

ME =1.753\frac{0.360}{\sqrt{16}}= 0.158

Now we have everything in order to replace into formula (1):

3-1.753\frac{0.360}{\sqrt{16}}=2.842    

3+1.753\frac{0.360}{\sqrt{16}}=3.158    

So on this case the 90% confidence interval would be given by (2.842;3.158)    

3 0
4 years ago
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