Answer:
If Kristen were to make 4 batches, and each batch requires 2 cups of flour, how many cups of flour would she need? To solve this question, we would just multiply 4 by 2, which gives us a final product of 8.
Similarly, in this question, if one batch requires 1 3/4 cups of flour and Kristen wants to bake 3 1/2 batches, she would need 1 3/4 x 3 1/2 cups of flour.
1 3/4 can be rewritten as an improper fraction- 7/4.
3 1/2 can also be rewritten as an improper fraction- 7/2.
Multiplying 7/4 and 7/2, we obtain a final product of 49/8, or 6 1/8.
This means, Kristen will need 6 1/8 cups of flour to make 3 1/2 batches, and her belief that she needs 3 3/8 cups of flour is wrong, as she needs a lot more than that.
Hope this helps!
These are two separate problems: in the first we will have to substitute in a new value for x into the original equation and in the second we will manipulate the preexisting equation for f(x).
To begin, we will sub in f(x/3). To do this, we will substitute each variable x in the equation (in this case there is only one) with x/3, and then simplify the resulting equation.
f(x) = 6x - 18
f(x/3) = 6(x/3) - 18
To simplify, we should distribute the 6 on the right side of the equation.
f(x/3) = 6x/3 - 18
Now, we can divide the first term on the right side to finalize our simplification.
f(x/3) = 2x -18
Secondly, we are asked to find f(x)/3. To do this, we will take our original value for f(x), and then simplify divide that entire function by 3.
f(x) = 6x - 18
f(x)/3 = (6x-18)/3
This means that we must divide each term of the binomial by 3, so we are really computing
f(x)/3 = 6x/3 - 18/3
We can simplify by dividing both of the terms.
f(x)/3 = 2x - 6
Therefore, your answer is that f(x/3) = 2x - 18, but f(x)/3 = 2x - 6. It is important to recognize that these are two similar, yet different, answers.
Hope this helps!
An=A1 r ^(n-1)
192= 3 r ^(4-1)
192 = 3 r^3
64 = r^3
r = 4
equation:
An=3 (4)^(n-1)
6th term:
An= 3 (4)^(6-1)
An= 3072
I think this is right :)
{(-2, 6), (-5, -1), (3, 7), (-5, 0)}
Domain: The domain is all the x-values (-2, -5, 3, -5)
Range: The range is all the y-values (6, -1, 7, 0)
Function: It's not a function because of the x-value -5 is repeating.
