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VikaD [51]
3 years ago
7

Company A charges $50 rental fee and $20 per hour.Then Company B charges $35 rental fee and $25 per hour.At which hour do both c

ompanies cost the same ?
Mathematics
2 answers:
Scrat [10]3 years ago
4 0

Answer:

Hour 3.

Step-by-step explanation:

                          A                                 B

Hour 1               $ 70                             $60

Hour 2              $90                              $85

Hour 3              $110                             $110

KengaRu [80]3 years ago
3 0
For company a it would be at the 8th hour and they would be 210 and for company b it would be at the 7th hour
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A researcher wishes to​ estimate, with 9090​% ​confidence, the proportion of adults who have​ high-speed Internet access. Her es
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Answer:  a) Required minimum sample size= 219

b) Required minimum sample size= 271

Step-by-step explanation:

As per given , we have

Margin of error : E= 5% =0.05

Critical z-value for 90% confidence interval : z_{\alpha/2}=1.645

a) Prior estimate of true proportion: p=28%=0.28

Formula to find the sample size :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.28(1-0.28)(\dfrac{1.645}{0.05})^2\\\\=218.213856\approx219

Required minimum sample size= 219

b) If no estimate of true proportion is given , then we assume p= 0.5

Formula to find the sample size :-

n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.645}{0.05})^2\\\\=270.6025\approx271

Required minimum sample size= 271

8 0
3 years ago
Solve x2 – 12x + 36 = 90 for x.
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A: x= 6+3 squareroot 10 ... Its letter A

4 0
3 years ago
Convert 0.00001 to a power of 10. <br> 104 <br> 10−4 <br> 105 <br> 10−5
11111nata11111 [884]

Answer:

10^5

Step-by-step explanation:

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5 0
3 years ago
On which interval is the average rate of change for bicycle production the greatest? A) 1950 to 1960 B) 1960 to 1970 C) 1970 to
Alborosie

Answer:

D) 1980 to 2000

Step-by-step explanation:

Finding the average rate of change in each interval to determine the greatest one.

Production per interval

1950-1960 = (21-11) \ million = 10 million

1960-1970 = (41-21)\ million = 20 million

1970-1980 = (71-41)\ million = 30 million

1980-2000 = (161-71)\ million= 90 million

Rate of change (1950-1960)= \frac{10}{11} \times 100= 90.90\%

Rate of change (1960-1970) = \frac{20}{21} \times 100= 95.23\%

Rate of change (1970-1980)=  \frac{30}{41} \times 100= 73.17\%

Rate of change (1980-2000)= \frac{90}{71} \times 100= 126.76\%

∴ rate of change between 1980 to 2000 is 126.78%

7 0
3 years ago
What is the value of the expression?
KengaRu [80]

Answer:

<h2>B. -3.2</h2>

Step-by-step explanation:

4\!\!\!\!\diagup^1\cdot\dfrac{-6.4}{8\!\!\!\!\diagup_2}=-\dfrac{6.4}{2}=-3.2

8 0
3 years ago
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