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aleksandrvk [35]
3 years ago
6

PLEASE HELP QUICK!!!!!

Mathematics
2 answers:
astra-53 [7]3 years ago
4 0

Answer:

8

Step-by-step explanation:

check this out!

-5(a+3)=- 55

-5a-15=- 55

-5a= -55+15

-5a= -40

-5a/-5 =-40/-5

a=8

valkas [14]3 years ago
3 0

Answer:

Choice C is correct.

Step-by-step explanation:

We have given an equation :

-5(a+3)=-55

We have to solve it for a.

-5(a+3)= -55

-5a-15= -55

Adding 15 on both sides of equation we get,

-5a =  -55+15

Multiplying 1/-5 on both sides we get,

-5a = -40

a = -40/ -5

a = 8 is the answer.

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marishachu [46]
20 because 12 divided by 3 is 4. then you multiply 5 by 4. and you get 20.
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Answer:

The phase difference between yA and yB is  \frac{-\pi }{12}

Step-by-step explanation:

Given harmonic modeled as :

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The function as written as :

y = a sin(ωt  - Ф)  where  Ф is phase difference

So , phase difference between yA   and  yB = ( Ф_1 - Ф_2 )

Or phase difference between yA   and  yB = ( -  \frac{\pi }{3} + \frac{\pi }{4} )

Or, phase difference between yA   and  yB = (\frac{-4\pi +3\pi }{12})

I.e phase difference between yA   and  yB =\frac{-\pi }{12}

Hence The phase difference between yA and yB is \frac{-\pi }{12}   Answer

4 0
3 years ago
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Jane is building a bookcase with 4 shelves. Each shelf is 24 inches long. How much wood does Jane need to make the 4 shelves?
Ksivusya [100]

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Hope this helps!!! Good luck!!! ;)

7 0
3 years ago
Team tool bella canoed 15 3/4 miles in 5/4 hours. What was their average rate of speed in mph ​
luda_lava [24]

Average speed is 12.6 miles per hour

<em><u>Solution:</u></em>

Given that team tool bella canoed 15\frac{3}{4} miles in \frac{5}{4} hours

To find: average rate of speed in miles per hour

From given information,

distance = 15\frac{3}{4} \text{ miles } = \frac{15 \times 4+3}{4} = \frac{63}{4} \text{ miles}

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To find the speed we use the below formula,

speed = \frac{distance}{time}

Substituting the given values we get,

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7 0
3 years ago
What is the solution to 3x+30+x=10+2x+5x+2?
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Answer:

answer is x = 6

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I hope it helps you

:-))

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