Its all up to you and how hard you are willing to work to get that may credits in one semester. But you could do it. Hope that helped!
Answer:
(-1, -1) Let me know if the explanation didn't make sense.
Step-by-step explanation:
If we graph the three points we can see what looks like a quadrilateral's upper right portion, so we need a point in the lower left. This means M is only connected to N here and P is only connected to N. So we want to find the slope of these two lines.
MN is easy since their y values are the same, the slope is 0.
NP we just use the slope formula so (y2-y1)/(x2-x1) = (-1-3)/(5-4) = -4.
So now we want a line from point M with a slope of -4 to intersect with a line from point P with a slope of 0. To find these lines weuse point slope form for those two points. The formula for point slope form is y - y1 = m(x-x1)
y-3 = -4(x+2) -> y = -4x-5
y+1 = 0(x-5) -> y = -1
So now we want these two to intersect. We just set them equal to each other.
-1 = -4x -5 -> -1 = x
So this gives us our x value. Now we can plug that into either function to find the y value. This is super easy of we use y = -1 because all y values in this are -1, so the point Q is (-1, -1)
9a^2-6ab+12ac-8bc
=3a(3a-2b)+4c(3a-2b)
=(3a+4c)(3a-2b)
There you go. Have fun!
