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shutvik [7]
3 years ago
11

Determine the degree measure of arc HJ. A) 27° B) 35.5° C) 44° D) 62.5°

Mathematics
2 answers:
Ratling [72]3 years ago
8 0
C Would Be Correct I Belive
Nezavi [6.7K]3 years ago
6 0

Answer

Find the degree measure of arc HJ.

To prove

By using the formula

Angle\ formed\ outside = \frac{1}{2} (Difference\ of\ intercepted\ arcs)

i.e

\angle HOJ =\frac{1}{2}(98^{\circ} - measure\ of\ arc\ HJ. )

As ∠HOJ = 27°

Put in the above equation

27^{\circ}=\frac{1}{2}(98^{\circ} - measure\ of\ arc\ HJ. )

27° × 2 =  98° - measure of arc HJ

54° = 98° - measure of arc HJ.

measure of arc HJ = 98° - 54°

measure of arc HJ = 44°

Therefore the option (C) is correct.

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How many area codes (abc) would be possible if all three digits could be any vaiue 1-9
kifflom [539]

Answer:

<u>The total number of area codes that would be possible if all three digits could be any value from 1 to 9 is 729.</u>

Step-by-step explanation:

1. Let's start our reasoning to get this answer:

From 000 to 999, we have 1,000 possible area codes.

But for this question, we should find out the answer without considering the digit 0, therefore we must exclude:

A. From 000 to 099, that are 100 possible area codes.

B. We also have to exclude, from 100 to 110, 120, 130, 140, 150, 160, 170, 180 and 190. Those are 19 area codes more.

C. We also have to exclude these same options of code areas, for 200 - 210 and 2x0, and 19 more for each subset that starts with 3, 4, 5, 6, 7, 8 and 9. In total, 19 multiplied by 8, 152 numbers more.

<u>Therefore, the total number of area codes that would be possible if all three digits could be any value from 1 to 9 is:</u>

<u>1,000 - 100 - 19 - 152 = 729</u>

<u>The simplest way to find it, is:</u>

<u>For 000 to 999 = 1,000 or 10³</u>

<u>Excluding the digit zero = 729 or 9³</u>

3 0
3 years ago
W(n) = n + 3; Find the value of w(-5)<br> A) 2 <br> B) -2<br> C) 3<br> D) 1
Lina20 [59]

Answer:

-2

Step-by-step explanation:

-5 + 3 = -2

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

6 0
3 years ago
Write 9x² - 36x = 4y² + 24y + 36 in standard form
Kisachek [45]

Answer:

9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;

(x - 2)²/2² - (y + 3)²/3² = 1

Step-by-step explanation:

The standard form of a hyperbola is given as follows;

(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1

The given equation is presented as follows;

9·x² - 36·x = 4·y² + 24·y + 36

By completing the square, we get;

(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)

(3·x - 6)² - 36 = (2·y + 6)²

(3·x - 6)² - (2·y + 6)² = 36

(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1

(3·x - 6)²/6² - (2·y + 6)²/6² = 1

3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1

(x - 2)²/2² - (y + 3)²/3² = 1

The equation of the hyperbola  is (x - 2)²/2² - (y + 3)²/3² = 1.

5 0
3 years ago
A triangle with vertices at A(0,0),B(0,4),and C(6,0) is dilated to yield a triangle with vertices at A'(0,0),B'(0,10), and C'(15
kakasveta [241]
You can use 4/10 or 6/15
5 0
3 years ago
Read 2 more answers
Equuations were b=11 is a solution
goldenfox [79]

22=2b

66=6b

50=b+39

2=b-9

4 0
4 years ago
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