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3 years ago

Please help with these ones okay

Mathematics

1 answer:

bija089 [108]3 years ago

6 0

Answer:

D, I don't know, and 1 + 3

Step-by-step explanation:

D I'm not 100% sure on, 2 I have no clue, and the third is just swapping the signs because you are flipping over the axis. I hope I could help you!

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Bill and Mary Ann went to the Viola bakery. Bill bought 5 pies and 7 donuts for $12.65. Mary Ann bought 6 of each for $12.30.

sweet [91]

Answer:

Pies=$0.85

Donuts= $1.20

Step-by-step explanation:

In the equation let p stand for the number of pies and d stand for the number of donuts.

To solve this set up 2 equations, one representing bill and the other representing Mary Ann.

Bill's equation is 5p+7d=$12.65.
Mary Ann's equation is 6p+6d=$12.30

Then solve using a system of equations. Systems of equations can be solved using elimination or substitution. I will use substitution. Solve bill's equation for p. This gives you $p=\frac{12.65-7d}{5}$ . Then, you can substitute that into Mary Ann's equation. This looks like $6\cdot \frac{12.65-7d}{5}+6d=12.3$ . Solve for d. Once you solve d=1.20. Finally, substitute 1.20 back into either Bill's or Mary Ann's for d and solve for p. No matter which equation you use p=0.85.

3 0

2 years ago

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}$

Apply the <u>zero-product property</u> and solve for x:

$\implies x+1=0 \implies x=-1$

$\implies x-5=0 \implies x=5$

Substitute the found values of x into the <u>second equation</u> and solve for y:

$\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}$

$\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}$

Therefore, the solutions are:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

6 0

1 year ago

Read 2 more answers

What is another way to write this number 300+70+1/5+8/100

barxatty [35]

Answer:

370.28

Step-by-step explanation:

you add the two whole numbers then you add the two fractions and make them a decimal after that put it all together and u get the answer

3 0

3 years ago

Simplify the expression. (3x/y)^-3

AysviL [449]

Answer:

y^3/(27 x^3)

Step-by-step explanation:

Simplify the following:

((3 x)/y)^(-3)

((3 x)/y)^(-3) = (y/(3 x))^3:

(y/(3 x))^3

Multiply each exponent in y/(3 x) by 3:

(y^3)/((3 x)^3)

Multiply each exponent in 3 x by 3:

y^3/(3^3 x^3)

3^3 = 3×3^2:

y^3/(3×3^2 x^3)

3^2 = 9:

y^3/(3×9 x^3)

3×9 = 27:

Answer: y^3/(27 x^3)

6 0

3 years ago

Each calendar will sell for $5 each write an equatio to model the total income for selling calendars

Brrunno [24]

To answer the question above, I let x be the number of calendars sold. You may use any other letter as this is just for representation. The total income generated in selling calendars is calculated by multiplying the number of calendars with the price. That is,
total income = 5x
If we let total income be y, our equation is further simplified into,
y = 5x

4 0

3 years ago