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Sergio [31]
3 years ago
5

How to write 6,173,253 in expanded form

Mathematics
2 answers:
Nata [24]3 years ago
7 0

Expanded form:

6 x 1000000 + 1 x 100000 + 7 x 10000 + 3 x 1000 + 2 x 100 + 5 x 10 + 3 x 1

Word form:

six million, one hundred seventy three thousand two hundred fifty three.

masha68 [24]3 years ago
5 0

6173253 = (6 x 100000000) + (0 x 10000000) + (1 x 1000000) + (7 x 100000)+ (3 x 10000) + (0 x 1000) + (2 x 100) + (5 x 10) + (3 x 1)

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$ 65.59 more per week

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(ASAP PICTURE ADDED) What is the simplified form of the following expression?
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Answer:

option c is correct.

Step-by-step explanation:

7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)

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Now, We will find factors of the terms inside the square root

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Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

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(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)

So, option c is correct

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3 years ago
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