The corresponding point to the point given (3,5) which is on the graph of f(x) as described in the task content is; (3,6).
<h3>What is the corresponding point to the given point (3,5) as given in the task?</h3>
It follows from the task content that the point given originally is; (3,5).
However, it is required that the point which is equivalent to the given point on the graph of y=(x+2)+1 be identified.
It therefore follows that the point required as in discuss is;
y = (3+2) +1
y = 6.
Hence, the corresponding point is; (3,6).
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Answer:
If we define the random variable X ="time spend by the students doign homework"
And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:
Null hypothesis: 
Alternative hypothesis: 
And they wnat to use a sample size of n = 100 and a significance level of 0.05
Step-by-step explanation:
Previous concepts
A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".
The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".
The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".
Solution to the problem
If we define the random variable X ="time spend by the students doign homework"
And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:
Null hypothesis: 
Alternative hypothesis: 
And they wnat to use a sample size of n = 100 and a significance level of 0.05
Answer:
5,3 I think or 5,4
Step-by-step explanation:
Answer:
w
=
q
z
+
4
Step-by-step explanation:
Solve for w by simplifying both sides of the equation, then isolating the variable.