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Volgvan
3 years ago
15

Need Help ASAP, I'M CONFUSED, IF YOU CAN'T ANSWER DON'T ANSWER

Mathematics
1 answer:
jeka943 years ago
4 0
<span>A perpendicular bisector of a line segment is a line segment perpendicular to and passing through the midpoint of (left figure). The perpendicular bisector of a line segment can be constructed using a compass by drawing circles centered at and with radius and connecting their two intersections.

Hope i helped

</span>
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Prove that sin(n) diverges
Ivahew [28]
If you look at the graph of sin(n), you can notice that it oscillates every kpi/2 when k is odd. This oscillation proves that sin(n) diverges.
8 0
3 years ago
Six times the quantity, x-2, is 24. Find the number, x.
pychu [463]

Answer:

x = 6

Step-by-step explanation:

Hope this helps!

=)

6 0
3 years ago
Read 2 more answers
SOMEONE PLEASE HELLPPPP
ipn [44]

Answer:

93.39

Step-by-step explanation:

So the sum of exterior angles of the convex octagon is: 360 degrees

This means if we add all the equations that represent each angle, we can set it equal to 360 and solve for x

(x+14) + (2x-3) + (3x+8) + (3x+16) + (2x-17) + (3x-4) + (3x-12) + (6x)

Group like terms

(x+2x+3x+3x+2x+3x+3x+6x) + (14-3+8+16-17-4-12)

Add like terms

23x+2

Now let's set the sum of exterior angles to 360

23x+2 = 360

Subtract 2 from both sides

23x=358

Divide both sides by 23

x\approx 15.565

So by looking at all these, it appears that 6x is the highest value, given that x is positive. The way I estimated, is approximately 15.5, whenever I saw an equation like x+14, I estimated it's about 2x, since 14 is not exactly, but close to 15.5. I did this with each polynomial given. You could also manually check each one

Original equation

6x

Subsitute

6(15.565)

Simplify

93.39

7 0
1 year ago
5(2+(-9))+-25<br> HELP<br> PLZZ
Gelneren [198K]
Answer: -60

Step by step
5 (2 - 9) -25
Start by distributing which will give you
10 - 45 - 25
Combine your like terms giving you
-60
7 0
2 years ago
Read 2 more answers
A car of 1000 kg starts to move from rest and travels a distance of 150 m in 10 second. How much force is needed?​
allsm [11]
  • Initial velocity=u=0m/s
  • Distance=s=150m
  • Time=t=10s
  • Acceleration=a

Using second equation of kinematics

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto 150=0(10)+\dfrac{1}{2}a(10)^2

\\ \sf\longmapsto 150=\dfrac{1}{2}\times 100a

\\ \sf\longmapsto 50a=150

\\ \sf\longmapsto a=\dfrac{150}{50}

\\ \sf\longmapsto a=3m/s^2

  • Mass=m=1000kg
  • Force=F

Using newtons second law

\\ \sf\longmapsto F=ma

\\ \sf\longmapsto F=1000(3)

\\ \sf\longmapsto F=3000N

3 0
2 years ago
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