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Katena32 [7]
3 years ago
11

Use the wrap text icon to

Computers and Technology
1 answer:
velikii [3]3 years ago
3 0

click on the image and there should be an icon with an upside dwon "U" and lines, click that and select wrap text icon.... or any other text thing you see fit

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It is (D) because FAT 32 is the most secure option that is why it is most popular
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How is the pattern matching done in the SQL?
Alinara [238K]

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SQL pattern matching allows you to search for patterns in data if you don't know the exact word or phrase you are seeking. This kind of SQL query uses wildcard characters to match a pattern, rather than specifying it exactly. For example, you can use the wildcard "C%" to match any string beginning with a capital C.

Explanation:

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True false) ther are five arrow keys on the keborad​
cluponka [151]

Answer:

false, there's only 4

Explanation:

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3 years ago
A contiguous subsequence of a list S is a subsequence made up of consecutive elements of S. For example, if S is 5,15,-30,10,-5,
Sindrei [870]

Answer:

We made use of the dynamic programming method to solve a linear-time algorithm which is given below in the explanation section.

Explanation:

Solution

(1) By making use of the  dynamic programming, we can solve the problem in linear time.

Now,

We consider a linear number of sub-problems, each of which can be solved using previously solved sub-problems in constant time, this giving a running time of O(n)

Let G[t] represent the sum of a maximum sum contiguous sub-sequence ending exactly at index t

Thus, given that:

G[t+1] = max{G[t] + A[t+1] ,A[t+1] } (for all   1<=t<= n-1)

Then,

G[0] = A[0].

Using the above recurrence relation, we can compute the sum of the optimal sub sequence for array A, which would just be the maximum over G[i] for 0 <= i<= n-1.

However, we are required to output the starting and ending indices of an optimal sub-sequence, we would use another array V where V[i] would store the starting index for a maximum sum contiguous sub sequence ending at index i.

Now the algorithm would be:

Create arrays G and V each of size n.

G[0] = A[0];

V[0] = 0;

max = G[0];

max_start = 0, max_end = 0;

For i going from 1 to n-1:

// We know that G[i] = max { G[i-1] + A[i], A[i] .

If ( G[i-1] > 0)

G[i] = G[i-1] + A[i];

V[i] = V[i-1];

Else

G[i] = A[i];

V[i] = i;

If ( G[i] > max)

max_start = V[i];

max_end = i;

max = G[i];

EndFor.

Output max_start and max_end.

The above algorithm takes O(n) time .

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3 years ago
Gaming related
Blababa [14]

Answer:

yes affects your K/D

Explanation:

winner winner chicken dinner

please mark me please brainliest or mark thanks

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