This question s incomplete, the complete question is;
The Watson family and the Thompson family each used their sprinklers last summer. The Watson family's sprinkler was used for 15 hours. The Thompson family's sprinkler was used for 30 hours.
There was a combined total output of 1050 of water. What was the water output rate for each sprinkler if the sum of the two rates was 55L per hour
Answer:
The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Step-by-step explanation:
Given the data in the question;
let water p rate for Watson family and the Thompson family sprinklers be represented by x and y respectively
so
x + y = 55 ----------------equ1
x = 55 - y ------------------qu2
also
15x + 30y = 1050
x + 2y = 70 --------------equ3
input equ2 into equ3
(55 - y) + 2y = 70
- y + 2y = 70 - 55
y = 15
input value of y into equ1
x + 15 = 55
x = 55 - 15
x = 40
Therefore, The Watson family sprinkler is 40 L/hr while Thompson family sprinkler is 15 L/hr
Answer:
7, 8.5, 10
Step-by-step explanation:
It is adding 1.5 every time
(can I get brainliest now)
You add the two numbers and divide by two to get their average, of the number that would be midway (also a midpoint for visualization) between them. Find the least common denominator, which should be 9. Thus, you will multiply both the numerator and denominator of 7/3 by 3 to retain the ratio. You should get 21/9. Now, add 21/9 and 5/9 to get 26/9. That should be your answer, but make it a mixed number so you don't have an improper fraction.
