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sertanlavr [38]

3 years ago

8

Can someone help me solve #9!?

1 answer:

yarga [219]3 years ago

4 0

Dy/dx = (4y²)(x⁴/³)

Find ∫(4y²)(x⁴/³) =∫(4y²∛(x⁴)dx = 3∛(x⁴).y² +c or 3x⁴/³.y² + c

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What Is the area of the trlangle? Enter the answer in the box.<br> square units

WITCHER [35]

Answer: right

Step-by-step explanation:

7 0

3 years ago

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This is super confusing plz help???

netineya [11]

Answer:

None. She gave half to one person then the other half to another person.

Step-by-step explanation:

Hope this is correct, if not feel free to let me know. I'm sorry in advance if this is wrong.

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2 years ago

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The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require

grigory [225]

Answer:

142.2 meters.

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.

Let us find total surface area of box using surface area formula of cuboid.

$\text{Total surface area of cuboid}=2(lb+bh+hl)$ , where,

$l$ = Length of cuboid,

$b$ = Breadth of cuboid,

$w$ = Width of cuboid.

$\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)$

$\text{Total surface area of box}=2(2520+432+840)$

$\text{Total surface area of box}=2(3792)$

$\text{Total surface area of box}=7584$

Therefore, the total surface area of box will be 7584 square cm.

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

$\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}$

$80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2$

$\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}$

$\text{ Length of canvass}=14220\text{ cm}$

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}$

$\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}$

$\text{ Length of canvass}=142.20\text{ m}$

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0

3 years ago

Please help me with this question!!

aleksklad [387]

Answer:

it would be J

Step-by-step explanation:

the number line is going 1 in both directions from zero, the question is asking you to find what -1/2 is on the other side of the number line, so you are looking for 1/2 k is 1/4 and L is -1/4

7 0

3 years ago

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4. Describe the proportion method for solving a percentage problem:

kondor19780726 [428]

Step-by-step explanation:

Consider the provided information.

For the proportion method first set up the equation like this:

$\frac{Part}{Whole}=\frac{Percentage}{100}$

Perform the cross multiplication and then solve for the missing part.

For example:

Find 80 percentage of 10.

Step 1: Set up the equation.

$\frac{Part}{10}=\frac{80}{100}$

$\frac{Part}{10}=\frac{4}{5}$

Step 2: Perform the cross multiplication

$Part=\frac{4}{5}\times 10$

Step 3: Solve for the missing part.

$Part=4 \times 2$

$Part=8$

3 0

3 years ago

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