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sertanlavr [38]

3 years ago

8

Can someone help me solve #9!?

1 answer:

yarga [219]3 years ago

4 0

Dy/dx = (4y²)(x⁴/³)

Find ∫(4y²)(x⁴/³) =∫(4y²∛(x⁴)dx = 3∛(x⁴).y² +c or 3x⁴/³.y² + c

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Please help Ladder question!!

PIT_PIT [208]

Answer:

Step-by-step explanation:

This is a related rates problem from calculus using implicit differentiation. The main equation is going to be Pythagorean's Theorem and then the derivative of that. Pythagorean's Theorem is

$x^2+y^2=c^2$ where c is the hypotenuse and is a constant. Therefore, the derivative of this with respect to time, and using implicit differentiation is

$2x\frac{dx}{dt}+2y\frac{dy}{dt}=0$ and dividing everything by 2 to simplify a bit:

$x\frac{dx}{dt}+y\frac{dy}{dt}=0$ . Upon analyzing that equation, it looks like we need values for x, y, $\frac{dx}{dt}$ , and $\frac{dy}{dt}$ . And here's what we were given:

$\theta=45$ and $\frac{dx}{dt}=.5$ In the greater realm of things, that's nothing at all.

BUT we can use the right triangle and the angle we were given to find both x and y. The problem we are looking to solve is to

Find $\frac{dy}{dt}$ at the instant that $\frac{dx}{dt}$ = .5.

Solving for x and y:

$tan45=\frac{x}{6}$ and

6tan45 = x ( and since this is a 45-45-90 triangle, y = x):

$6(\frac{\sqrt{2} }{2})=x=y$ so

$x=y=3\sqrt{2}$ and now we can fill in our derivative. Remember the derivative was found to be

$x\frac{dx}{dt}+y\frac{dy}{dt}=0$ so

$3\sqrt{2}(\frac{1}{2})+3\sqrt{2}\frac{dy}{dt}=0$ and

$\frac{3\sqrt{2} }{2}+3\sqrt{2} \frac{dy}{dt}=0$ and

$3\sqrt{2}\frac{dy}{dt}=-\frac{3\sqrt{2} }{2}$ and multiplying by the reciprocal of the left gives us:

$\frac{dy}{dt}=-\frac{3\sqrt{2} }{2}(\frac{1}{3\sqrt{2} })$ so

$\frac{dy}{dt}=-\frac{1}{2}\frac{m}{s}$

8 0

3 years ago

A science fair poster is a rectangle 46 inches long and 36 inches wide. What is the area of the poster in square feet?

Aleksandr-060686 [28]

Hello,

46 × 36 = 1 656 inches²

Bye :)

6 0

4 years ago

When Does The Median Represent A Typical Jump Better Than The Mean Does?

larisa86 [58]

Well the median is the middle number, so I would say whenever the mean is lower than the median

3 0

3 years ago

X^2+14x-15=0 solve by completing square<br>

Softa [21]

Answer:

${x}^{2} + 14x - 15 = 0 \\ {x}^{2} - x + 15x -15 = 0 \\ x(x - 1) + 15(x - 1) = 0 \\ (x - 1)(x + 15) = 0 \\ \boxed{x = 1} \\ \boxed{x = - 15}$

<h3><u>x=1 and x=</u><u>-</u><u>15</u> is the right answer.</h3>

7 0

3 years ago

3(2x+5) = 2(3x+3). V.

zhenek [66]

Answer: no solution, try going into more detail. Sorry if this isnt helpful

Step-by-step explanation:

5 0

3 years ago