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ella [17]
2 years ago
13

Find the Area of the figure below, composed of a rectangle and a semicircle. Round to

Mathematics
1 answer:
Ostrovityanka [42]2 years ago
6 0

Answer:

129.1 square units

Step-by-step explanation:

First, let's find the area of the rectangle. We can use the formula below.

a=lw

where l is the length and w is the width.

The length of the rectangle is 13 and the width is 8.

l=13\\w=8

Substitute the values into the formula.

a=13*8

a=104

Next, let's find the area of the semicircle. We can use the formula below.

a=\frac{1}{2} *\pi r^2

First, find the radius. The radius is half of the diameter, and the diameter is 8.

⇒ r= d/2

⇒ r= 8/2

⇒ r= 4

a=\frac{1}{2} *\pi (4)^2

Evaluate the exponent.

⇒ 4² = 4*4 = 16

a=\frac{1}{2} *\pi *16

Multiply pi and 16.

a=\frac{1}{2} *50.2654825

Multiply.

a=25.1327412

Finally, find the area of the figure.

Add the area of the rectangle (104) and the area of the semicircle (25.1327412)

104+25.1327412

129.132741

Round to the nearest tenth. The 3 in the hundredth place tells us to leave the 1 in the tenth place.

129.1

The area of the figure is about 129.1 (square units).

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Step-by-step explanation:

Pentagon a = 4.9 in. s = 7.1 in. /l ;/ >cvr'-. ~ j-?.1· '19~~. 5) Octagon a = 20.8 m s= 17.2m. ,4 ~;.>a-rt. ::: i, 17. z • t~f "g. ~ :::::, l'/?1 ,0 nt z, ... What is the length of the apothem to the nearest whole number

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The point (5, -1) is a solution of the equation: y = 2x − 11 question 28 options: true false
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I need help with #47 to #50 ASAP…. Please help me with it
Ksenya-84 [330]

Step-by-step explanation:

a triangular number n is the sum of all natural numbers <= n.

t1 = 1

t2 = 1+2 = 3

t3 = 1+2+3 = 6

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...

so,

tn = tn-1 + n

47.

1×8 + 1 = 9 is a square number.

3×8 + 1 = 25 is a square number

6×8 + 1 = 49 is a square number

10×8 + 1 = 81 is a square number

48.

1/3 = 0 remainder 1

3/3 = 1 remainder 0

6/3 = 2 remainder 0

10/3 = 3 remainder 1

15/3 = 5 remainder 0

21/3 = 7 remainder 0

28/3 = 9 remainder 1

so, there seems to be a pattern 1 0 0 1 0 0 1 0 0 1 ...

49.

1/4 = 0 remainder 1

4/4 = 1 remainder 0

9/4 = 2 remainder 1

16/4 = 4 remainder 0

25/4 = 6 remainder 1

36/4 = 9 remainder 0

49/4 = 12 remainder 1

so, there seems to be a pattern 1 0 1 0 1 0 1 0 1 0 1 ...

50.

polygonal numbers is the real name for this.

the formula for dimensions = 5 is

(3n² − n)/2

for dimensions = 6 it is

2n² - n

so, dimensions=5 (and therefore dividing also by 5) we get the remainders

1/5 = 0 remainder 1

5/5 = 1 remainder 0

12/5 = 2 remainder 2

22/5 = 4 remainder 2

35/5 = 7 remainder 0

51/5 = 10 remainder 1

70/5 = 14 remainder 0

92/5 = 18 remainder 2

117/5 = 23 remainder 2

145/5 = 29 remainder 0

here the pattern is 1 0 2 2 0 1 0 2 2 0 1 0 2 2 0 ...

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6/6 = 1 remainder 0

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28/6 = 4 remainder 4

45/6 = 7 remainder 3

66/6 = 11 remainder 0

91/6 = 15 remainder 1

120/6 = 20 remainder 0

153/6 = 25 remainder 3

190/6 = 31 remainder 4

231/6 = 38 remainder 3

276/6 = 46 remainder 0

325/6 = 54 remainder 1

here the pattern is 1 0 3 4 3 0 1 0 3 4 3 0 1 0 3 4 3 0 ...

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