D.
If we take a sample of 100g of the given compound, we should find that it contains 74.1g of oxygen and 25.9g of nitrogen. The molar masses of oxygen and nitrogen are approximately 16.0g/mol and 14.0g/mol respectively. To find the appropriate number of moles of oxygen and nitrogen found in one mole of the given compound, we divide the mass of the sample by the molar mass of each substance.
For oxygen: 74.1g/(16.0g/mol) = 4.63125 mol (round up to 5 mol)
For nitrogen: 25.9g/(14.0g/mol) = 1.85 mol (round up to 2 mol)
Therefore one mole of this compound contains 2 moles of nitrogen and 5 moles of oxygen.
Its mass will stay the same
The amount of heat required to melt 15.0 grams of ice at 0.0º C is<u> 4950 J.</u>
<h3>What is the amount of heat required to melt 15.0 grams of ice at 0.0º C?</h3>
The amount of heat required to melt 15.0 grams of ice at 0.0º C is calculated from the formula given below:
Amount of heat = mass * latent heat of fusion of ice
The latent heat of fusion is the amount of heat required to convert a unit mass of ice at 0.0º C to water at 0.0º C
The latent heat of fusion of ice is 330J/g
mass of ice = 15.0 g
Amount of heat required = 15.0 g * 330 J/g
Amount of heat required = 4950 J
Learn more about latent heat of fusion at: brainly.com/question/87248
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Answer:
3,200 joules
Explanation:
q = mcΔT = (250.0 g)(0.128 j/g°C)(100°C -25°C) = 3,200 joules
Assume 100 g of compound. This turns percent to mass. Calculate moles:
S ---> 30/32 = 0.9375
F ---> 70 / 19 = 3.6842
get whole number ratio:
0.9375 / 0.9375 = 1
3.6842 / 0.9375 = 3.93 = 4
Answer : SF4
