Answer:
The z-score for a data value of 121 is -2.29.
Step-by-step explanation:
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the z-score for a data value of 121.
This is Z when X = 121. So
The z-score for a data value of 121 is -2.29.
Answer
C. (5/2, -1/3)
Step by step explanation
Here we use the rational root theorem.
The possible roots are
+1, +3, +5, +15, +1/2, +3/2, +5/2, +15/2, +1/3, +5/3, +1/6 and +5/6
We have to use the synthetic division to find the correct root of this function.
Here the roots are 5/2 and -1/3
Others are not roots of this function.
Let's check x = 5/2 with synthetic division.
5/2) 6 -13 13 -39 -15
- 15 5 45 15
--------------------------
6 2 18 6 0
Similarly x = -1/3 is also root of this function.
Answer: C. (5/2, -1/3)
Answer:
21.46 cm²
Step-by-step explanation:
because the question want only for the SHADED REGION but NOT AREA OF THE SQUARE
(if we just multiply 10x10. you will get the area of a square which is hundered)
To find the shaded region:
1. area of a circle is πr² (we have 4 circle there)
2. Find the area of all circle
# how do we know the radius?
- half of 10 is 5
- 5 is the diameter of each circle
- the radius is half of 5 which is 2.5
- π(2.5)² = 25/4π (area of 1 circle)
3. since we have 4 circle then, 25/4π x 4 = 25π
4. the area of the square is 100cm²
5. we want the shaded region so we have to minus the area of the circle
6. 100 - 25π (use your calculator to find the answer)
answer should be 21.46 cm²
(hope this helps)
(y - 5)/3 = 1
y - 5 = 3 x 1 = 3
y = 3 + 5 = 8
6x + 29 = 5
6x = 5 - 29 = -24
x = -24/6 = -4
