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Rudiy27
2 years ago
13

Evaluate 1+ (-2/3)- (-m) where m=9/12

Mathematics
1 answer:
Agata [3.3K]2 years ago
6 0

Answer:

13/12

Step-by-step explanation:

1-2/3+9/12

least common denominator is 12

12/12 - 8/12+9/12

13/12

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3<br><img src="https://tex.z-dn.net/?f=%203%5Cfrac%7B4%7D%7B5%7D%20%20%5Cdiv%20%203%5Cfrac%7B1%7D%7B6%7D%20" id="TexFormula1" ti
Jobisdone [24]
Hey There!

Here is your answer:

First write the equation down:

-3 4/5 ÷ -3 1/6

Then put the mixed fractions into whole numbers:

-3 4/5= 5×-3=-15+4=-11= -11/5
&
-3 1/6= 6×-3=-18+1=-17= -17/6

Now right the new problem:

-11/5×6/-17

Now multiply:

-11×6=-66
5×-17=-85

Which means -66/-85 is your answer!

Hope this helps!
3 0
3 years ago
If the student is a domain/inout and the hair color is the range/output how is these two set of relation not a function?
IRINA_888 [86]

Answer:

A function is a relation that maps inputs from a set called the domain, into outputs from a set called the range.

Such that each input can be mapped into only one output.

So for example, if we have a relation that maps the input 2 into two different values:

f(2) = 4

f(2) = 8

Then this is not a function.

In the case of the problem, we have a student as the input, and the hair color as the output.

So we will have something like:

f(student) = blond

And if this student decides to change his/her hair color to red?

Then the function becomes:

f(student) = red

So for the same input, we had two different outputs, which means that this is not a function.

We also could have the case where a given student has two colors (Californian for example)

Where again, we would see two different outputs for one single input.

6 0
2 years ago
Using the simple random sample of weights of women from a data​ set, we obtain these sample​ statistics: nequals45 and x overbar
Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : n=45

\overline{x}=148.79\text{ lb}

\sigma=31.37\text{ lb}

a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = \mu=148.79\text{ lb}

b) The confidence interval for the population mean is given by :-

\mu\ \pm E, where E is the margin of error.

Formula for Margin of error :-

z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given : Significance level : \alpha=1-0.90=0.1

Critical value : z_{\alpha/2}=z_{0.05}=\pm1.645

Margin of error : E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69

Now, the 90% confidence interval for the population mean will be :-

148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)

Hence, the 90​% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

3 0
3 years ago
Helpppp meee plsssss
Sholpan [36]

Answer:

B

Step-by-step explanation:

1/6x+ 4/6x = -4/6

5/6x= -4/6

x=( -4/6)/ (-5/6)

x= 4/5

8 0
2 years ago
Can anyone solve this:
ludmilkaskok [199]
So fuctions mean
if
f(x)=x+2 then if you put in 3 for x then
f(3)=3+2=5 so

if x=years after 2000
in 2020 then
2020-2000=20 so x=20
subsitute
f(20)=9204e^0.022(20)

e could be:
1. common base of logarithms (memorised to 15 decmals) 2.718281828459045
2. a computer notation exg if you have 3e11 that means 3 times 10^11

if it is 1
9240 times (2.718281828459045^(0.022 times 20))=( simplify exponent first) 9240 times (2.718281828459045^0.44)=9204 times 1.5527072185113=14291.1 or rounded to 14291

if it is 2
9204 times 10^(0.022 times 20)=9204 times 10^(0.44)=9204 times 254.491 rounded to 254


so the answer dependes on what e represents,

if e is:
1. common base of logarithms (memorised to 15 decmals) 2.718281828459045, then answer is 14291

2. a computer notation exg if you have 3e11 that means 3 times 10^11 =254

7 0
3 years ago
Read 2 more answers
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