All categories

3 years ago

What is the approximate solution to the equation 2^t =38

Mathematics

1 answer:

timurjin [86]3 years ago

3 0

2^t =38

take the log of each side

log ( 2^t) = log (38)

the exponent gets multiplies

t log (2) = log (38)

divide by log 2

t = log(38)/log (2)

t≈5.2479

You might be interested in

Adiciones racinales 1/7+3/7+2/7

Digiron [165]

6/7 is the awnser for this one

7 0

2 years ago

The inverse of the function graphed below is a function.<br><br>A. True<br>B. False

Anuta_ua [19.1K]

False. In order to have an inverse, your function must pass the horizontal line test. The graph fails the test.

7 0

2 years ago

Read 2 more answers

Geometry help needed. more information in the picture. please help. would be greatly appreciated.

ratelena [41]

Answer:

Step-by-step explanation:

180-120=60so the answer is a 60

4 0

2 years ago

A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas

WITCHER [35]

Answer:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

$P(A) = 0.8, P(B) = 0.2$

We are assuming that the two events are independent so then we have the following propert:

$P(A \cap B ) = P(A) * P(B)$

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

$P(B' \cup A')$

And using the De Morgan laws we know that:

$(A \cap B)' = A' \cup B'$

So then we can write the probability like this:

$P(B' \cup A') = P((A \cap B)')$

And using the complement rule we can do this:

$P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)$

Since A and B are independent we have:

$P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32$

And then our final answer would be:

$P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68$

5 0

2 years ago

a shelf holds 3 novels, 2 biographies, and 1 history book. two students in turn choose a book at radom. what is the probability

shepuryov [24]

1/2 choose biographies

3 0

2 years ago