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White raven [17]
2 years ago
15

Which fraction is equivalent to 70/100

Mathematics
1 answer:
Viefleur [7K]2 years ago
6 0

Answer:

710

Step-by-step explanation:

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Which sequence of rigid transformations will map the preimage ABC onto image A'B'C' ?
iren2701 [21]

Answer:

The answer is option A, a double reflection

5 0
3 years ago
Which ordered pairs represent points on the graph of f(x)= Negative RootIndex 3 StartRoot x EndRoot? Check all that apply.
DedPeter [7]

Answer:

  • (0, 0)
  • (1, –1)
  • (8, –2)

Step-by-step explanation:

We normally think of the ordered pairs as ...

  (x, y) = (x, -∛x)

Another way to think about them is ...

  (x, y) = (-y³, y)

I find it a little easier to think about the cube of a number, rather than its cube root.

For the y-values given, -2, -1, 0, 2, the points that will be on the graph are ...

  (8, -2), (1, -1), (0, 0), (-8, 2)

The first three of these points are listed in your answer choices.

7 0
3 years ago
Read 2 more answers
Suppose that each time Giannis Antetokounmpo shoots a free throw, he has a 3/4 probability of success. If Giannis shoots three f
GREYUIT [131]

Answer:

84.38% probability that he succeeds on at least two of them

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

He has a 3/4 probability of success.

This means that p = \frac{3}{4} = 0.75

Giannis shoots three free throws

This means that n = 3

What is the probability that he succeeds on at least two of them

P(X \geq 2) = P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.75)^{2}.(0.25)^{1} = 0.4219

P(X = 3) = C_{3,3}.(0.75)^{3}.(0.25)^{0} = 0.4219

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4219 + 0.4219 = 0.8438

84.38% probability that he succeeds on at least two of them

6 0
2 years ago
Please help me on this problem!!!
skelet666 [1.2K]

Answer:

2.79166666667

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A tractor was purchased for $30,000 six years ago. what is the value of the tractor today if the depreciation rate was 2.5%?
MrRissso [65]
Initial cost = $30,000
Depreciation rate = 2.5%

Depreciation expense per year = 30,000*2.5/100 = $750
In six years,
Depreciation = 6*750 = $4,500

Value of the tractor = Initial cost - Depreciation = $30,000 - $4,500 = $25,500
6 0
2 years ago
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