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3 years ago

Which of the following is an arithmetic sequence?

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

5 0

Answer:B

Step-by-step explanation:

please add Brainliest

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Damon has 14 white socks, 6 black socks, and 4 blue socks in his drawer. If he chooses two socks at random, what is the possibil

strojnjashka [21]

If ur answer can be a fraction then it’d be 14/24 or 7/12 chance

4 0

3 years ago

For any three consecutive numbers, prove algebraically that the largest number and the smallest number are factors of the number

Burka [1]

"For any three consecutive numbers": x,y,z:
x
y=x+1
z=x+2

"prove algebraically that the largest number and the smallest number are factors"
x*z=

"of the number that is one less than the square of the middle number"

=y²-1

x*z=y²-1
x*(x+2)=(x+1)²-1
x²+2x=x²+2x+1-1
x²+2x=x²+2x

both sides of the equation are the same, so the statement is correct

8 0

3 years ago

Suppose Cesar Chavez lead a March with 6,300 people. If the ratio of marchers who were not farmworkers to farmworkers is 4:5, ho

baherus [9]

Answer:

3500.

Step-by-step explanation:

We have been given that Cesar Chavez lead a March with 6,300 people. The ratio of marchers who were not farm-workers to farm-workers is 4:5. We are asked to find the number of marchers, who were farm-workers.

First of all, we will find the ratio of farm-workers to total marchers as:

$\frac{\text{Farm-workers}}{\text{Total marchers}}=\frac{\text{Farm-workers}}{\text{Farm-workers+non-farm-workers}}=\frac{5}{4+5}=\frac{5}{9}$

To find the number of marchers, who were farm-workers, we need to find $\frac{5}{9}$ of whole marchers.

$\text{Number of marchers that were farm-workers}=6300\times \frac{5}{9}$

$\text{Number of marchers that were farm-workers}=700\times \frac{5}{1}$

$\text{Number of marchers that were farm-workers}=3500$

Therefore, 3500 marchers were farmers.

4 0

3 years ago

Given the following system of equations, identify the type of system. x + y = 6 y = 3 - x

jolli1 [7]

This system of equations has no solution, the 2 lines will never cross

5 0

3 years ago

Different cereals are randomly selected and the sugar content in grams of sugar per grams of cereal are obtained. Use a .05 sign

Elanso [62]

Answer:

Step-by-step explanation:

Hello!

X: content of sugar of a sample of cereal.

Data set:

0.03, 0.24, 0.30, 0.47, 0.43, 0.07, 0.47, 0.13, 0.44, 0.39, 0.48, 0.17, 0.13, 0.09, 0.45, 0.43

n= 16

$\frac{}{X}$ = 0.295g

S= 0.17g

You have to test if the mean sugar content is less than 0.3g

H₀: μ ≥ 0.3

H₁: μ < 0.3

α: 0.05

Assuming that the variable has a normal distribution, you have to conduct a t test:

$t= \frac{\frac{}{X}-Mu }{\frac{S}{\sqrt{n} } } ~~t_{n-1}$

$t_{H_0}= \frac{0.295-0.30}{\frac{0.17}{\sqrt{16} } } = -0.12$

p-value: 0.4533

The p-value is greater than α, the decision is to not reject the null hypothesis.

At a 5% significance level the decision is to not reject the null hypothesis. You can conclude that the average sugar content of the cereal is equal or greater than 0.3g of sugar per gram of cereal.

I hope this helps!

7 0

3 years ago