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Oksana_A [137]
3 years ago
14

An animal shelter spends $2.50 per day to care for each cat and $4.00 per day to care for each dog. Camden noticed that the shel

ter spent $100.50 caring for cats and dogs on Thursday. Camden found a record showing that there were a total of 30 cats and dogs on Thursday. How many cats were at the shelter on Thursday?
Mathematics
1 answer:
svp [43]3 years ago
3 0

Answer: 13 cats were at the shelter on Thursday.

Step-by-step explanation:

Let x represent the number of cats that were at the shelter on Thursday.

Let y represent the number of dogs that were at the shelter on Thursday.

Camden found a record showing that there were a total of 30 cats and dogs on Thursday. This means that

x + y = 30

The animal shelter spends $2.50 per day to care for each cat and $4.00 per day to care for each dog. Camden noticed that the shelter spent $100.50 caring for cats and dogs on Thursday. This means that

2.5x + 4y = 100.5 - - - - - - - - - - - - 1

Substituting x = 30 - y into equation 1, it becomes

2.5(30 - y) + 4y = 100.5

75 - 2.5y + 4y = 100.5

- 2.5y + 4y = 100.5 - 75

1.5y = 25.5

y = 25.5/1.5

y = 17

x = 30 - y = 30 - 17

x = 13

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svetlana [45]

Answer:

B

Step-by-step explanation:

P=2L+2W

P-2L=2W (Subtract 2L from both sides of the equation)

2W=P-2L (Symmetric Property of Equality)

W=\frac{P-2L}{2} (Divide both sides of the equation by 2)

W=\frac{P}{2} -\frac{2L}{2} ("Split" the fractions)

W=\frac{1}{2}P-L (Simplify)

Hope this helps!

4 0
2 years ago
You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each)
Kazeer [188]

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

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Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1, v_1 = = 20 m./s

Velocity of the truck 2,v_2 = 35 m./s

1. Kinetic energy of the truck 1:\frac{1}{2}mv_{1}^2=\frac{1}{2}\times 3000 kg\times (20 m/s)^=600,000 joules

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2.a) Energy loose by the truck 1:

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Potential energy of truck 1 at that height = mgh=3000\times 9.8 m/s^2\times 22 m=646,800 Joules

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

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576=z^2+144

z^2=576-144

z^2=432

z=√432

z=√144*3

z=12√3

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