Answer:
13. A
14. C.
Step-by-step explanation:
A relation is a function if there is only one y assigned to each x.
That is if you have a set of points, there should be no repeated x value.
So looking at {(0,0),(-2,4),(-2,-4),(-3,7)} this is not a function because you have two x's that are the same. A.
The slope-intercept form of a linear equation is y=mx+b where m is the slope and b is the y-intercept.
The y-intercept is where the graph goes through the y-axis at. It goes through at -1 so b=-1.
The slope is rise/run. So starting from the y-intercept (0,-1) we need to find another point to count the rise & run to... How about (3,1)? That works. You can do the counting if you want. You could also use the slope formula.
To use the slope formula, I just like to line the points up vertically and subtract vertically then put 2nd difference over the 1st difference.
(0,-1)
-(3,1)
--------
-3 -2
So the slope is -2/-3 or just 2/3.
So the equation is y=2/3 x-1
C.
Let the original price of the sweater be = X
Then the amount Jerome pays for the sweater after 20% discount = X - (20X/100)
= X - 0.2X
= 0.8X
Now on this price the 8.25% tax needs to be added to get to the amount actually paid by Jerome.
So,
0.8X + [(8.25/100) * (0.8X) = 25.1
This is the equation from which the actual price of the sweater bought by Jerome can be determined.
So
0.8X + [(.0825) * ( 0.8X) = 25.1
0.8X + 0.066X = 25.1
0.866X = 25.1
X = 25.1/0.866
= 28.98
So the actual price of the sweater is $28.98.
Answer:5/100, 5/10, 50/100
Step-by-step explanation:
The <span>given the piecewise function is :
</span>
![f(x) = \[ \begin{cases} 2x & x \ \textless \ 1 \\ 5 & x=1 \\ x^2 & x\ \textgreater \ 1 \end{cases} \]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5C%5B%20%5Cbegin%7Bcases%7D%20%0A%20%20%20%20%20%202x%20%26%20x%20%5C%20%5Ctextless%20%5C%20%201%20%5C%5C%0A%20%20%20%20%20%205%20%26%20x%3D1%20%5C%5C%0A%20%20%20%20%20%20x%5E2%20%26%20x%5C%20%5Ctextgreater%20%5C%201%20%0A%20%20%20%5Cend%7Bcases%7D%0A%5C%5D)
To find f(5) ⇒ substitute with x = 5 in the function → x²
∴ f(5) = 5² = 25
To find f(2) ⇒ substitute with x = 5 in the function → x²
∴ f(2) = 2² = 4
To find f(-2) ⇒ substitute with x = 5 in the function → 2x
∴ f(-2) = 2 * (-2) = -4
To find f(1) ⇒ substitute with x = 1 in the function → 5
∴ f(1) = 5
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So, the statements which are true:<span>
</span><span>
</span>
