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Gala2k [10]
3 years ago
12

What is a possible value of sin(theta) when cos2(theta)=0.73?

Mathematics
1 answer:
Sindrei [870]3 years ago
8 0
We use the following trigonometric identity to answer the question:
 sin^ 2 (theta) + cos^ 2 (theta) = 1
 We substitute the values:
 sin ^ 2 (theta) + 0.73 = 1
 We cleared:
 sin ^ 2 (theta) = 1-0.73
 sin ^ 2 (theta) = 0.27
 Answer:
 a possible value of sin ^ 2 (theta) is:
 
c.0.26 (nearest option)
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<img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B2%7D%7B15y%7D%20%20%2B%20%20%5Cfrac%7B3%7D%7B5y%20%7B%7D%5E%7B3%7D%20%7D" id="
Xelga [282]

Answer:

2y²   +   9

---------------

      15y³

Step-by-step explanation:

Start by identifying the LCD, and then change each fraction so that its denominator is the LCD.

Here the LCD is 15y³, which is evenly divisible by 15y and 5y³.

Focus now on the first fraction:  2 / (15y).  Multiplying numerator and denominator of this fraction by y² results in

y²·2          2y²

--------- → ----------

y²·15y       15y³           ←This is the correct LCD

Multiplying numerator and denominator of the second fraction by 3 results in:

   3·3            9

------------ → ---------

 3·5y³         15y³          ←This is the correct LCD

So now those two original terms look like:

 2y²         9

--------- + --------

 15y³       15y³

and this can be written in simpler form as:

2y²   +   9

---------------

      15y³

3 0
4 years ago
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