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3 years ago

12

What is a possible value of sin(theta) when cos2(theta)=0.73?

1 answer:

Sindrei [870]3 years ago

8 0

We use the following trigonometric identity to answer the question:
sin^ 2 (theta) + cos^ 2 (theta) = 1
We substitute the values:
sin ^ 2 (theta) + 0.73 = 1
We cleared:
sin ^ 2 (theta) = 1-0.73
sin ^ 2 (theta) = 0.27
Answer:
a possible value of sin ^ 2 (theta) is:
c.0.26 (nearest option)

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Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

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We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

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$x^{3}+7 x^{2}+12 x=0$

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Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

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we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

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Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

$\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}$

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$\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}$

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$\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}$

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3 years ago

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RoseWind [281]

Answer:

$\displaystyle m=2$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

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Coordinates (x, y)
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Step-by-step explanation:

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<em>Find points from graph.</em>

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Point (-9, -8)

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Stells [14]

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