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Andrei [34K]
3 years ago
13

Find the value of x. Round the length to the nearest tenth. The diagram is not drawn to scale.

Mathematics
1 answer:
rodikova [14]3 years ago
4 0

For the given triangle, the value of x is 2,880.2 m.

Step-by-step explanation:

Step 1:

The sum of the angles on a straight line is 90°. It is given that the sum of the upper sides angle and 10° is 90°.

So the triangle has an angle of 80° on the top side.

Step 2:

For the top side, the hypotenuse measures x m and the adjacent side measures 500 m.

To determine the value of x, we determine the cos of the given angle.

cos \theta = \frac{adjacentside}{hypotenuse} , cos 80 = 0.1736, cos 80 = \frac{500}{x}.

x = (500)(0.1736) = 2,880.1843.

So rounding this off, we get the value of x is 2,880.2 m.

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The client is to receive cyclophosphamide (Cytoxan) 50 mg/kg intravenously in divided doses over 5 days. The client weighs 176 p
marishachu [46]

Answer:

800 mg

Step-by-step explanation:

As the excerpt states that the client weights 176 pounds and is to receive cyclophosphamide (Cytoxan) 50 mg/kg, we have to convert 176 pounds to kg:

1 kg → 2.20 pounds

  x   ←  176 pounds

x= (176 pounds * 1 kg)/2.20 pounds= 80 kg

Now, we have to determine the total amount of cyclophosphamide (Cytoxan) that the client has to receive:

50 mg/kg

For 80 kg: 80 kg *50 mg/kg= 4,000  mg

As the dose is divided over 5 days:

4,000 mg / 5= 800 mg

The client will receive 800 mg of cyclophosphamide each day.

6 0
3 years ago
How do you find the surface area of a cylinder with
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Answer:

2111.15

Step-by-step explanation:

A=2π*r*h+2π*r^2

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7 0
3 years ago
A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0
4 years ago
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