Answer:
Check the explanation
Step-by-step explanation:
a ) let u(1) is the population at a mean rate for the college students who are of the male gender.
u(2) is the population mean for female college students
H0:u(1) = u(2)
Ha:u(1) \neq u(2 )
2 ) using minitab>stat>basic stat>two sample t
we have
Two-Sample T-Test and CI
Sample N Mean StDev SE Mean
1 29 70.50 2.90 0.54
2 30 69.60 3.30 0.60
Difference = μ (1) - μ (2)
Estimate for difference: 0.900
95% CI for difference: (-0.722, 2.522)
T-Test of difference = 0 (vs ≠): T-Value = 1.11 P-Value = 0.271 DF = 57
Both use Pooled StDev = 3.1099
degree of freedom = 57
here p value will be two sided
3 ) using the output
t value = 1.11
p value = 0.271
4 ) since p value is greater than 001 so we will accept the null hypothesis .
we will conclude that average of male and female college basketball players are same
1 week = 7 days
Answer : Thomas spends $9.80 on food in one week.
Hope this helps. - M
Happy Pride Month!
Answer:
Option B
Step-by-step explanation:
Use Desmos graphing calculator for these probloms and type your qustion on the left box
Answer:
x = 5
Step-by-step explanation:
im too tired to explain just trust me
(5) + 2 = 7
2(5) + 3 = 13
13 * 7 = 91
