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4 years ago

8

Please help my homework’s due tomorrow and I need sleep help !!

2 answers:

Svetlanka [38]4 years ago

8 0

Answer:

6x-11y-z

Step-by-step explanation:

*note* Just like in the alphabet, the order of your answer will go x, y, then z.

1. The only numbers with x as a variable is 2x and +4x. You see that 4x has a plus sign in front so you should add 2x and 4x together which equals 6x.

2. The only numbers with y as a variable is -5y and -6y. The way you would write this is -5y (+) -6y. The plus sign doesn't affect the equation at all, so the answer would be -11y.

3. The only numbers with z as a variable is -2z and +(1)z (the 1 is basically invisible lol). You want to add -2z and z, which equals -(1)z, which is -z.

Dmitry [639]4 years ago

5 0

Answer

6x−11y−z

Step-by-step explanation:2x−5y−2z+4x−6y+z

=2x+−5y+−2z+4x+−6y+z

Combine Like Terms:

=2x+−5y+−2z+4x+−6y+z

=(2x+4x)+(−5y+−6y)+(−2z+z)

=6x+−11y+−z

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Ken can walk 40 dogs in 8 hours how many can ken walk in 12 hours

Jlenok [28]

It would half 8 hours to get 4 hours and 20 dogs
Next add the 4 hours and 20 dogs to the 8 hours and 40 dogs so
4+8=12 hours
20+40=60 dogs
So Ken can walk 60 dogs in 12 hours

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3 years ago

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4 years ago

Read 2 more answers

Who can help me d e f thanks

12345 [234]

d)

$y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}$

Product rule:

$y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'$

Chain and power rules:

$y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'$

Power rule:

$y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)$

Now simplify.

$y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

e)

$y = \dfrac{3bx + ac}{\sqrt{ax}}$

Quotient rule:

$y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}$

$y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}$

Power rule:

$y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}$

Now simplify.

$y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}$

$y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}$

$y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}$

f)

$y = \sin^2(ax+b)$

Chain rule:

$y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'$

$y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'$

$y' = 2a \sin(ax+b) \cos(ax+b)$

We can further simplify this to

$y' = a \sin(2(ax+b))$

using the double angle identity for sine.

7 0

2 years ago

Which of the following is NOT classified as nonverbal communication a. Signs b. Eye Contact c. Body language d. Gestures

Dafna11 [192]

Answer:

american sign language (ASL)

4 0

3 years ago

If x is not equal to zero, what is the value? show step by step.

Black_prince [1.1K]

Answer:

2/3

Step-by-step explanation:

Simplify the numerator

(2x) ^3 = 8 x^3

8x^3 * 3x = 24 x^4

Simplify the denominator

(6x^2) ^2 = 36 x^4

Simplify the fraction

24x^4/ 36 x^4 =

24/36 = 2/3

x^4/x^4 =1

The fraction is 2/3 when x does not equal 0

4 0

3 years ago