Answer:
Probability of obtaining no more than two defective tubes = 0.816
Step-by-step explanation:
The Probability of obtaining no more than two defective tubes in a randomly selected sample of 15 tubes is obtained using the binomial distribution formula: nCr × p^r × q^(n -r).
Where n is number of samples;
r is maximum number of defective tubes, r ≤ 2;
p is probability of defective tubes = 10% or 0.1
q is probability of non-defective tubes, q = 1 - p
Further explanations and calculations are given in the attachment below:
Answer:y=3/20+12m+6
Step-by-step explanation: The equation for these types of problems are y=mx+b
the y is the second number, so in the first one the y would be -6, so you replace the y with the -6 and the x with -12
so now the equation is -6=-12m+b
you add the -12m to the other side to make 12m+6=b
now onto the second one, the 9 is the y and the 8 is the x, now the equation is 9=8m+b
this time you replace the b with the equation you got earlier (12m+6=b)
So the equation is 9=8m+12m+6
minus the 6 on both sides
3=8m+12m
add the m's
3=20m
3/20=m
Now you replace the m and the b
y=3/20x+12m+6
(Hopefully im sorry if this isnint correct :) )
Answer:
To make a histogram for the data, you need to label on the x-axis 60-75, 76-90,91-105. Label on the y-axis 1,2, and 3.
Put 3 in the first bucket, 1 in the second, and 2 in the third.
