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kolbaska11 [484]
3 years ago
15

Given parallelogram EFGH with diagonals that intersect at point J, which statement is true? Diagonal segment EG is perpendicular

to diagonal segment FH. EJ = JG EG bisects angle E. All of the above are true.
Mathematics
1 answer:
Anna [14]3 years ago
7 0
E. All of the above are true. 
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Uber is now charging a $2.50 flat rate in addition to $0.75 per mile for your ride. Janae can spend at most $13 on her Uber Ride
Alex777 [14]

Answer:

  • B: 10

Step-by-step explanation:

<u>Full charge can be expressed as equation:</u>

  • c = 2.5 + 0.75m, where c- charge, m- miles

<u>The limit for charge is $13, then we got inequality:</u>

  • 0.75m + 2.5 ≤ 13
  • 0.75m ≤ 9.5
  • m ≤ 9.5/0.75
  • m ≤ 12.66

Option B: 10 is correct as the only number satisfying the inequality

7 0
3 years ago
Read 2 more answers
Help me plz, thanks.
adell [148]
It is going to be 3/10 because you simplify 6 blue/ 20 total marbles
6 0
3 years ago
Question 5 of 5
Allisa [31]

Answer:

I would say C not to sure tho

6 0
1 year ago
I need helpp hurry plzz!!!
wariber [46]

Answer:

B. 2x2

Step-by-step explanation:

5 0
2 years ago
Find the coordinates of the point (x,y,z) on the planez=4x+3y+1 which is closest to the origin.
Nataliya [291]
Given plane &Pi; : f(x,y,z) = 4x+3y-z = -1
Need to find point P on &Pi;  that is closest to the origin O=(0,0,0).

Solution:
First step: check if O is on the plane &Pi; : f(0,0,0)=0 &ne; -1 => O is not on &Pi;
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e. 
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane &Pi; , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane &Pi;
Answer: P(-2/13, -3/26, 1/26) is the point on &Pi; closest to the origin.

8 0
2 years ago
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